What is the implicit differentiation of y equals sin x plus y?

Answer 1

y = sin(x+y)

cos( x + y )[(1 + y')] = y'

cos(x + y ) + y'cos(x + y ) = y'

y'-y'cos( x+ y) = cos( x + y )

y'[1-cos(x+y)]= cos(x+y)

y'= [cos(x+y)]/ [1-cos(x+y)]