52 + 12x + 7 = 0
This is called a linear equation with one unknown (or one variable).
To solve it perform mathematical operations (addition, subtraction, multiplication, division) but whatever you do to one side of the equation, you must also do to the other side. Try to place the terms involving "x" on the left hand side and the remaining terms on the right hand side.
Subtract 52 from both sides.
52 - 52 + 12x + 7 = -52 : 12x + 7 = -52
Subtract 7 from both sides,
12x + 7 - 7 = -52 -7 : 12x = -59
If appropriate, divide both sides by 12
12x/12 = -59/12 : x = -59/12
If required, the answer could be converted into a decimal number :
x = -59/12 = -4.917 (3dp)
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95 plus 52 plus 95 plus 52 equals 294.
First, complete the square: x^2 - 12x + __ and y^2 + 8y + __.so we have x^2 - 12x + 36 = (x - 6)^2, and y^2 + 8y + 16 = (y + 4)^2.36 + 16 = 52, so we need to add 9 to both sides [43 + 9 = 52].so the equation is now: (x - 6)2 + (y + 4)2= 9 = 3 2, so the radius is 3.
122
308
54(x)+52+32(y)+72=212