0
Use the quadratic formula. In x2 + 12x + 13 = 0, a = 1, b = 12 and c = 3. The formula is:
-b +/- √(b2 - 4ac)
----------------------
2a
Thus, x = [-2 +/- √(122 - 4(1)(13))]/2(1) = [-2 +/- √(144 - 52)]/2 = [-2 +/- √92]/2 = -1 +/- √23.
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