The product is 2880x4y3. There is no equation nor inequality so it is not possible to find anything else.
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
The expression (2x + 2y) does not equal (2xy) or (4xy). Instead, it represents the sum of two terms, (2x) and (2y). If you factor it, you could write it as (2(x + y)), but it does not simplify to a product of (xy).
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
(2x)(2y) is the exact same as (2)(x)(2)(y) since they are all multiplication, which can be rearranged in any order, so this is also the same as (2)(2)(x)(y), which is the same as (4)(x)(y), so in the end: (2x)(2y)=4xy
To multiply (4x) by (-2y), you multiply the coefficients and the variables separately. The coefficients (4) and (-2) multiply to give (-8), while the variables (x) and (y) combine to form (xy). Therefore, the product of (4x) and (-2y) is (-8xy).
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
To multiply 2x by 2y, you would use the distributive property of multiplication over addition. This means you would multiply each term in the first expression by each term in the second expression. In this case, 2x * 2y would result in 4xy, as 2 * 2 equals 4 and x * y equals xy.
The expression (2x + 2y) does not equal (2xy) or (4xy). Instead, it represents the sum of two terms, (2x) and (2y). If you factor it, you could write it as (2(x + y)), but it does not simplify to a product of (xy).
xy(x - 2y)(x + 2y)
(2y)(2x - 3z)
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
Since 4xy2 is a factor of 20x2y4, it is automatically the GCF.
(x^2 + 2y)(x^3 - 2xy + y^3) = x^2(x^3 - 2xy + y^3) + 2y(x^3 - 2xy + y^3) Now, let's distribute each term: = x^2 * x^3 - x^2 * 2xy + x^2 * y^3 + 2y * x^3 - 2y * 2xy + 2y * y^3 Now, simplify each term: = x^5 - 2x^3y + x^2y^3 + 2x^3y - 4xy^2 + 2y^4 Now, combine like terms: = x^5 + x^2y^3 - 4xy^2 + 2y^4 So, the expanded form of (x^2 + 2y)(x^3 - 2xy + y^3) is x^5 + x^2y^3 - 4xy^2 + 2y^4.
(2x)(2y) is the exact same as (2)(x)(2)(y) since they are all multiplication, which can be rearranged in any order, so this is also the same as (2)(2)(x)(y), which is the same as (4)(x)(y), so in the end: (2x)(2y)=4xy
Multiply both sides by 2y. 1/2y = 7 1 = 14y y = 1/14
4xy + 6xz When factorising algebraic expressions treat them just as ordinary numbers. Ascertain what the common factors are. The factors of 4xy are 2 x 2 x 'x' x y The factors of 6xz are 2 x 3 x 'x' x z The factors common to both expressions are 2 and 'x'. Therefore, 4xy + 6xz = 2x(2y + 3z)
if you wish to multiply 3y-2y by 3y-y the answer is 2y^2