answersLogoWhite

0

(2x)(2y) is the exact same as (2)(x)(2)(y) since they are all multiplication, which can be rearranged in any order, so this is also the same as (2)(2)(x)(y), which is the same as (4)(x)(y), so in the end:

(2x)(2y)=4xy

User Avatar

Wiki User

15y ago

What else can I help you with?