0
How do i solve this Find three consecutive odd integers so that three times the second is 9 more than twice the third. What is the smallest number?
Yeah, I hate these too.
Identify the unknowns. Three consecutive odd integers will be x, x + 2 and x + 4
Set up the equation with the information you know.
Three times the second is 3 times (x + 2) which equals 3x + 6
Twice the third is 2 times (x + 4) which equals 2x + 8
The second is 9 more than the third so if we add 9 to the third, they will be equal.
3x + 6 = 2x + 8 + 9
Solve for x
3x + 6 = 2x + 17
3x = 2x + 11
x = 11
Always check your work. We think that the three integers are 11, 13 and 15
3 x 13 should be 9 more than 2 x 15
Since 39 is 9 more than 30, we got it right.
The answer asked for (the smallest integer) is 11.
Add your answer:
Earn +20 pts
The sum of two consecutive even integers is 50 what is the first number?
24. The second is 26.
Whats the answer to Find three consecutive even integers such that the sum of the smallest and twice the second is 20 more than the third?
Let the smallest integer be x. Since the consecutive even integers differ by 2, we havex + 2(x + 2) = (x + 4) + 203x + 4 = x + 24 (subtract x and 4 from both sides)3x - x - 4 + 4 = x - x - 4 + 242x = 20 (divide by 2 to both sides)x = 10Thus, the three consecutive even integers are 10, 12, and 14.
What is the sum of three consecutive integers if the sum of the first and third numbers is 33 less than 3 times the second number?
Their sum is 99.
Find 3 consecutive even integers if the product of the first integer and two two less than the second integer is four more than five times the third integer and what is the let statement?
The let statement is: let the smallest of the three integers be x.
Three consecutive odd integers such that four times the sum of the first and second is 7 less than 7 times the third?
Let's call the smallest of the consecutive odd integers x. Then the other ones are x+2 and x+4 respectively, and your equation becomes 4*(x+x+2)+7 = 7*(x+4) which is equivalent to 8x+15=7x+28 or x=13, so the consecutive integers you're looking for are 13, 15 and 17.
The sum of two consecutive even integers is 50 what is the first number?
24. The second is 26.
Given 3 consecutive integers with a sum of four times the second number write an algebraic equation?
i dont now
What is the second integer if three consecutive integers have the sum of 153?
51
What is the sum of two consecutive integers have the sum of 275?
I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.
Whats the answer to Find three consecutive even integers such that the sum of the smallest and twice the second is 20 more than the third?
Let the smallest integer be x. Since the consecutive even integers differ by 2, we havex + 2(x + 2) = (x + 4) + 203x + 4 = x + 24 (subtract x and 4 from both sides)3x - x - 4 + 4 = x - x - 4 + 242x = 20 (divide by 2 to both sides)x = 10Thus, the three consecutive even integers are 10, 12, and 14.
What is the sum of three consecutive integers if the sum of the first and third numbers is 33 less than 3 times the second number?
Their sum is 99.
What is the sum of 3 consecutive integers if the sum of the first and third number is two times the second number?
1, 2 and 3 -1, -2, and -3 6 or -6
Find 3 consecutive even integers if the product of the first integer and two two less than the second integer is four more than five times the third integer and what is the let statement?
The let statement is: let the smallest of the three integers be x.
If you take the 3 numbers in any consecutive integers and multiply them together to get a new number that new number will always be a multiple of 6 why is this?
18
Find the smallest of four consecutive even integers if twice the sum of the second and third integers is equal to the sum of the first and fourth integers increased by fourteen?
Since we know that the integers are even and consecutive, we can call them x, x+2, x+4, and x+6, with x being the smallest of the four. twice the sum of the second and third can be written as 2(x+2+x+4)=4x+12 the sum of the first and fourth increased by 14 is x+x+6+14=2x+20 Then we can solve 4x+12=2x+20-->2x=8-->x=4 4
Three consecutive odd integers such that four times the sum of the first and second is 7 less than 7 times the third?
Let's call the smallest of the consecutive odd integers x. Then the other ones are x+2 and x+4 respectively, and your equation becomes 4*(x+x+2)+7 = 7*(x+4) which is equivalent to 8x+15=7x+28 or x=13, so the consecutive integers you're looking for are 13, 15 and 17.
What is the smallest number which when added to an even number makes the sum an odd number?
Technically, there is no such thing as "the smallest number" since we can go into negative numbers and they go on forever. But if we are talking about positive integers, then the smallest would be 1 1 plus zero equals one. The second smallest would be 2 2 plus 1 equals 3
