Wiki User
∙ 6y agoYeah, I hate these too.
Identify the unknowns. Three consecutive odd integers will be x, x + 2 and x + 4
Set up the equation with the information you know.
Three times the second is 3 times (x + 2) which equals 3x + 6
Twice the third is 2 times (x + 4) which equals 2x + 8
The second is 9 more than the third so if we add 9 to the third, they will be equal.
3x + 6 = 2x + 8 + 9
Solve for x
3x + 6 = 2x + 17
3x = 2x + 11
x = 11
Always check your work. We think that the three integers are 11, 13 and 15
3 x 13 should be 9 more than 2 x 15
Since 39 is 9 more than 30, we got it right.
The answer asked for (the smallest integer) is 11.
Wiki User
∙ 6y ago24. The second is 26.
Let the smallest integer be x. Since the consecutive even integers differ by 2, we havex + 2(x + 2) = (x + 4) + 203x + 4 = x + 24 (subtract x and 4 from both sides)3x - x - 4 + 4 = x - x - 4 + 242x = 20 (divide by 2 to both sides)x = 10Thus, the three consecutive even integers are 10, 12, and 14.
Their sum is 99.
The let statement is: let the smallest of the three integers be x.
Let's call the smallest of the consecutive odd integers x. Then the other ones are x+2 and x+4 respectively, and your equation becomes 4*(x+x+2)+7 = 7*(x+4) which is equivalent to 8x+15=7x+28 or x=13, so the consecutive integers you're looking for are 13, 15 and 17.
24. The second is 26.
i dont now
I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.
51
Let the smallest integer be x. Since the consecutive even integers differ by 2, we havex + 2(x + 2) = (x + 4) + 203x + 4 = x + 24 (subtract x and 4 from both sides)3x - x - 4 + 4 = x - x - 4 + 242x = 20 (divide by 2 to both sides)x = 10Thus, the three consecutive even integers are 10, 12, and 14.
Their sum is 99.
The let statement is: let the smallest of the three integers be x.
1, 2 and 3 -1, -2, and -3 6 or -6
18
Since we know that the integers are even and consecutive, we can call them x, x+2, x+4, and x+6, with x being the smallest of the four. twice the sum of the second and third can be written as 2(x+2+x+4)=4x+12 the sum of the first and fourth increased by 14 is x+x+6+14=2x+20 Then we can solve 4x+12=2x+20-->2x=8-->x=4 4
Let's call the smallest of the consecutive odd integers x. Then the other ones are x+2 and x+4 respectively, and your equation becomes 4*(x+x+2)+7 = 7*(x+4) which is equivalent to 8x+15=7x+28 or x=13, so the consecutive integers you're looking for are 13, 15 and 17.
Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188