Wiki User
∙ 13y agoLet's call the smallest of the consecutive odd integers x. Then the other ones are x+2 and x+4 respectively, and your equation becomes 4*(x+x+2)+7 = 7*(x+4) which is equivalent to 8x+15=7x+28 or x=13, so the consecutive integers you're looking for are 13, 15 and 17.
Wiki User
∙ 13y ago18, 20 and 22
They are 14, 16 and 18.
Their sum is 99.
24. The second is 26.
The 3 consecutive odd positive integers are 7, 9 and 11.
18, 20 and 22
10-11-12
They are 14, 16 and 18.
Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.
The numbers are 14, 16 and 18.
Their sum is 99.
The 3 consecutive odd positive integers are 7, 9 and 11.
24. The second is 26.
n + 2(n+1) + 3(n+2) = 86 n + 2n + 2 + 3n + 6 = 86 6n = 86 - 2 - 6 6n = 78 n = 13 Three consecutive integers are = 13,14,15
the first number is x, the second x+1, third, x+2 and so on.so if the sum of three consecutive integers is 24, the setup would be this:x+x+1+x+2=24if it's consecutive even or odd integers the setup would be x, x+2, x+4,etc.so if the sum of three consecutive odd integers is 21, the setup would be:x+x+2+x+4=21for three or more even consecutive numbers, same setup
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.