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How do you solve 2x y 4?
Solve for y: f(-5)=13+2x
How do you solve f(x)2x-1?
I assume you mean: f(x) = 2x - 1 There is really nothing to "solve" here. This is the description of a function. For a specific value of "x", you can replace that value, to find out the value of the function. This is basically the same as evaluating: y = 2x - 1
What is the inverse of f(x)2x-7?
To find the inverse of the function ( f(x) = 2x - 7 ), we first replace ( f(x) ) with ( y ): ( y = 2x - 7 ). Next, we solve for ( x ) in terms of ( y ): ( x = \frac{y + 7}{2} ). Finally, we swap ( x ) and ( y ) to express the inverse function: ( f^{-1}(x) = \frac{x + 7}{2} ).
How do you find the inverse of the function f of x equals 2x plus 1 divide x-1?
y = f(x) = (2x + 1)/(x - 1)y*(x - 1) = (2x + 1) xy - y = 2x + 1xy - 2x = y + 1x(y - 2) = y + 1so x = (y + 1)/(y - 2) assuming y�2.So the inverse function is f-1(x) = (x + 1)/(x - 2)
Solve for x 2x - y equals 532?
-530
How do you solve 2x y 4?
Solve for y: f(-5)=13+2x
How do you solve f(x)2x-1?
I assume you mean: f(x) = 2x - 1 There is really nothing to "solve" here. This is the description of a function. For a specific value of "x", you can replace that value, to find out the value of the function. This is basically the same as evaluating: y = 2x - 1
How do you solve 2x-2y equals 1?
get it to y= -2y = 1 - 2x y = x - 0.5
What is the inverse of f(x)2x-7?
To find the inverse of the function ( f(x) = 2x - 7 ), we first replace ( f(x) ) with ( y ): ( y = 2x - 7 ). Next, we solve for ( x ) in terms of ( y ): ( x = \frac{y + 7}{2} ). Finally, we swap ( x ) and ( y ) to express the inverse function: ( f^{-1}(x) = \frac{x + 7}{2} ).
How do you find the inverse of the function f of x equals 2x plus 1 divide x-1?
y = f(x) = (2x + 1)/(x - 1)y*(x - 1) = (2x + 1) xy - y = 2x + 1xy - 2x = y + 1x(y - 2) = y + 1so x = (y + 1)/(y - 2) assuming y�2.So the inverse function is f-1(x) = (x + 1)/(x - 2)
How do you solve y equals y equals 2x-1 y equals 5x-13?
y = 2x -1 y = 5x -13 So: 5x -13 = 2x -1 5x -2x = 13 -1 3x = 12 x = 4 and by substituting y = 7
Solve for x 2x - y equals 532?
-530
Y plus 2x equals 0 solve for y?
y= -2x
Solve 2x-y equals 1 2x plus 5y equals -5?
X = 0 (zero) Y = -1 (neg 1)
How do you find the x and y intercept and middle point of y equals 2x plus 1?
To find the x-intercept, set y equal to zero (because that is where the line crosses the x-axis) and solve for x: y = 2x + 1 0 = 2x + 1 -2x = 1 x = -1/2 To find the y-intercept, set x equal to zero and solve for y: y = 2x + 1 y = 2*0 + 1 y = 1 The graph of this equation is a straight line that extends infinitely in both directions, therefore there is no "middle point."
When x is a number you do this to find y?
If you have a function, such as y=2x also written as f(x)=2x, then you plug in the number. So for example if x=1 then you have y=2 or f(1)=2.
How do you solve x plus y equals 4 and y equals 2X plus 1 by substitution method?
If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3
