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because if it is a multiple of 7 that means that 7 can go in to it evenly

ex: 7 factors:1,7

14:1,2,7,14

21:1,3,7,21

Q: How do know that 7 must be a factor each multiple of 7?

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Because it's the seven times table

The prime factorization of 32 is 2x2x2x2x2 or 25. The prime factorization of 40 is 2x2x2x5 or 23x5. For a number to be a multiple of a given number the multiple must have the entire prime factorization of that number in is. So a multiple of 32 must contain 2x2x2x2x2 or 25 . Likewise a multiple of 40 must contain 2x2x2x5 or 23x5. The least number that this could possible happen with must have 5 factors of 2 and one factor of 5 (the highest exponent on each individual prime factor). Thus the LCM is 2x2x2x2x2x5 or 25x5 Which is 160.

In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.

The measurements must be equal to each other.

By definition, any multiple of 130 must have 130 as a factor. Therefore no such number can be a prime.

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Because it's the seven times table

It must be 10.

The greatest common factor of two (or more) integers is the biggest whole number that divides into each one of them. The least common factor is the smallest whole number that divides into each one of them and must be 1. Very possibly, you meant the least common multiple, however?

The prime factorization of 32 is 2x2x2x2x2 or 25. The prime factorization of 40 is 2x2x2x5 or 23x5. For a number to be a multiple of a given number the multiple must have the entire prime factorization of that number in is. So a multiple of 32 must contain 2x2x2x2x2 or 25 . Likewise a multiple of 40 must contain 2x2x2x5 or 23x5. The least number that this could possible happen with must have 5 factors of 2 and one factor of 5 (the highest exponent on each individual prime factor). Thus the LCM is 2x2x2x2x2x5 or 25x5 Which is 160.

In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.

9720

Even.

There is no such number. If a multiple of 4 is a factor of 30, then 4 must also be a factor of 30, but 4 is not a factor of 30 (the factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30), thus no such number exists.

492 is an even number so it must be divisible by 2. Its digits total a multiple of 3 so it must be divisible by 3. Any even number that is divisible by 3 is divisible by 6. Of course, you can always divide 492 by 6. If it comes out even, it's a factor. (It does.)

The measurements must be equal to each other.

The numerator must contain the unit INTO which you are converting.

The measurements must be equal to each other.