38 = 26x - 7x 38 = 19x (38/19) = x 2 = x
26x = 156 Divide both sides of the equation by 26 to find the value of x: x = 6
The answer to this equation would be 5. This is a math problem.
(x2 + 26x +) : syntax error.x2 + 26x
I'm hearing x2 + 26x + ? = 0 where you want to know what the ? would be for a perfect square binomial.I would be remiss if I did not mention that this is not the best method for solving this equation. First, the best method:x2 + 26x = 0First, just factor the x from the left side:x(x + 26) = 0Then x = 0 or -26. Problem solved, two answers.If you really want to complete the square, you can still solve it, but it takes a bit longer. Take half of the middle number (26) which is 13 and then square it. 132=169. That is your question mark. Don't forget to add it to the 0 to keep the equation balanced:x2 + 26x + 169 = 0 +169To finish solving:(x + 13)2 = 169x + 13 = +/-13x = -13-13 or x = 13-13x = -26 or x = 0. Same answer as above. A heckuvalot more complicated.* * * * *While all of the above is true, completing the squares is a very powerful way of solving general quadratic equations. It is implicitly the same as using the quadratic formula.The question can arise when you want to solve an equation such asx2 + 26x + 25 = 0The first step is to rewrite it asx2 + 26x = -25Now complete the square on the left, by adding 169 to both sides.x2 + 26x + 169 = -25 + 169 x2 + 26x + 169 = 144(x + 13)2 = 12Take square rootsx + 13 = ± 12so x = -13 ± 12so that x = -1 or x = 25The number 25 was chosen deliberately so that, after adding 169 there would be a perfect square. But the method works equally well otherwise.*****That is all true, but not the original equation and certainly not the most efficient way to solve it. I never claimed "completing the squares" was not "a very powerful way of solving general quadratic equations". I simply stated, "I would be remiss if I did not mention that this is not the best method for solving this equation."
Sure. You can always 'solve for' a variable, and if it happens to be the only variable in the equation, than that's how you solve the equation.
it is not an equation (there no equality in it!)
To solve an equation it is sometimes helpful to do what to the original operation?
Solve the following equation for A : 2A/3 = 8 + 4A
The quadratic formula cannot be used to solve an equation if the coefficient of the equation's x2-term is 0.
Use a variable to represent the unknown. 'Translate' the words to math symbols and write an equation to solve. Solve the equation. Check.
There is no equation to solve, only an expression.
It depends on the equation that you're trying to solve.
x2 + 26x + 48 = (x + 24)(x + 2)
3x2+26x+16 When factorised: (3x+2)(x+8)
evaluate the equation, find the answer check the answer
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