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It seems like there might be a typographical error in your equation "26x 74." If you meant to write an equation such as "26x = 74," you can solve for ( x ) by dividing both sides by 26. This gives ( x = \frac{74}{26} ), which simplifies to ( x = \frac{37}{13} ) or approximately ( 2.85 ). If you meant something else, please clarify!
What else can I help you with?
How Do You Solve 26x-7x equals 38?
To solve the equation (26x - 7x = 38), first combine like terms on the left side. This simplifies to (19x = 38). Next, divide both sides by 19 to isolate (x), giving (x = 2). Thus, the solution is (x = 2).
How do you solve 38 equals 26x - 7x?
38 = 26x - 7x 38 = 19x (38/19) = x 2 = x
26x equals 156 how much is x?
26x = 156 Divide both sides of the equation by 26 to find the value of x: x = 6
What is the solution of 20x 2-26x plus 8 0?
The answer to this equation would be 5. This is a math problem.
X2 plus 26x plus?
(x2 + 26x +) : syntax error.x2 + 26x
How Do You Solve 26x-7x equals 38?
To solve the equation (26x - 7x = 38), first combine like terms on the left side. This simplifies to (19x = 38). Next, divide both sides by 19 to isolate (x), giving (x = 2). Thus, the solution is (x = 2).
How do you solve 38 equals 26x - 7x?
38 = 26x - 7x 38 = 19x (38/19) = x 2 = x
26x equals 156 how much is x?
26x = 156 Divide both sides of the equation by 26 to find the value of x: x = 6
What is the solution of 20x 2-26x plus 8 0?
The answer to this equation would be 5. This is a math problem.
X2 plus 26x plus?
(x2 + 26x +) : syntax error.x2 + 26x
How do you solve the equation -74x-6-1?
To solve the equation (-74x - 6 - 1 = 0), first combine the constants (-6) and (-1) to get (-74x - 7 = 0). Next, isolate (x) by adding (7) to both sides, resulting in (-74x = 7). Finally, divide both sides by (-74) to find (x = -\frac{7}{74}).
Where are the points of intersection on the x axis when y equals 8x squared -26x plus 15?
To find the points of intersection on the x-axis, set y equal to zero and solve for x. So, 8x^2 - 26x + 15 = 0. This is a quadratic equation that can be factored or solved using the quadratic formula. Once you find the values of x, those are the points of intersection on the x-axis.
What number is needed to complete the square x2 plus 26x equals 0?
I'm hearing x2 + 26x + ? = 0 where you want to know what the ? would be for a perfect square binomial.I would be remiss if I did not mention that this is not the best method for solving this equation. First, the best method:x2 + 26x = 0First, just factor the x from the left side:x(x + 26) = 0Then x = 0 or -26. Problem solved, two answers.If you really want to complete the square, you can still solve it, but it takes a bit longer. Take half of the middle number (26) which is 13 and then square it. 132=169. That is your question mark. Don't forget to add it to the 0 to keep the equation balanced:x2 + 26x + 169 = 0 +169To finish solving:(x + 13)2 = 169x + 13 = +/-13x = -13-13 or x = 13-13x = -26 or x = 0. Same answer as above. A heckuvalot more complicated.* * * * *While all of the above is true, completing the squares is a very powerful way of solving general quadratic equations. It is implicitly the same as using the quadratic formula.The question can arise when you want to solve an equation such asx2 + 26x + 25 = 0The first step is to rewrite it asx2 + 26x = -25Now complete the square on the left, by adding 169 to both sides.x2 + 26x + 169 = -25 + 169 x2 + 26x + 169 = 144(x + 13)2 = 12Take square rootsx + 13 = ± 12so x = -13 ± 12so that x = -1 or x = 25The number 25 was chosen deliberately so that, after adding 169 there would be a perfect square. But the method works equally well otherwise.*****That is all true, but not the original equation and certainly not the most efficient way to solve it. I never claimed "completing the squares" was not "a very powerful way of solving general quadratic equations". I simply stated, "I would be remiss if I did not mention that this is not the best method for solving this equation."
Can you solve for a variable in an equation?
Sure. You can always 'solve for' a variable, and if it happens to be the only variable in the equation, than that's how you solve the equation.
Do you answer an equation?
you don't answer an equation, you solve an equation
What is 26x - 4 equals 25?
26x-4 = 25 +4 +4 26x = 29 x= 29/26 or 1.115...
What are some ways to solve an equation?
solve it
