x2 + 20x + 4 = 0 x2 + 20x + 100 = 96 (x + 10)2 = 96 x + 10 = ±961/2 x = -10 ±961/2 x = -10 ±4√6
x2=20x 0 is an obvious solution if x is not 0, then divide both side by x, so x=20 so the solutions are 0 and 20
Factorises as (5x-2)(5x-2) so x = 0.4 25x2= 4, -20x = -8 4 - 8 + 4 = 0
They touch each other at (0, 100) on the x and y axis.
19x+1x+37=0 First add the 19x and 1x together 20x+37=0 Next subtract 37 to the other side 20x=-37 Now divide both sides by 20 x=-20/37
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
5x2 + 20x = 0 5x(x + 4) = 0 x = 0 and -4
50x squared equals 20x-2 equals zero is not possible, for 20x-2 = 0 --> x = 1/10 While 50x2 = 0 means that x should be zero. So either 50x2 =/ 20x-2 or 20x-2 =/ 0
If: 20x+80y = 0 Then: 80y = -20x And: y = -0.25x So the slope is -0.25 and it has no y intercept
20x + 80y = 0Subtract 20x from each side of the equation:80y = -20xDivide each side by 80:y = -1/4 xm = -1/4b = 0
The discriminant is 0.
The graphs of the two equations will intersect when x² + 20x + 100 = y = x² - 20x + 100 Subtracting x² +100 from both sides you get 20x = -20x that will only be true when x = 0. At x = 0, y = 100 for both equations - so the point of contact would be (0,100)
x2 + 20x + 4 = 0 x2 + 20x + 100 = 96 (x + 10)2 = 96 x + 10 = ±961/2 x = -10 ±961/2 x = -10 ±4√6
x2=20x 0 is an obvious solution if x is not 0, then divide both side by x, so x=20 so the solutions are 0 and 20
x2 + 20x - 39 = 0: Add 61 giving: x2 + 20x + 100 = (x + 10)2
Factorises as (5x-2)(5x-2) so x = 0.4 25x2= 4, -20x = -8 4 - 8 + 4 = 0
x2 + 36 = 20x so x2 - 20x + 36 = 0 so x2 - 2x - 18x + 36 = 0 or x(x - 2) - 18(x - 2) = 0 that is (x - 2)(x - 18) = 0 so x - 2 = 0 or x - 18 = 0 ie x = 2 or x = 18