IL
This is because I is 1 and L is 50. When a letter with a smaller value is placed just in front of a letter with a larger value, the small value must be subtracted from the larger value. So, 50-1 = 49.
Wrong
Corect Answer is = XLIX
and the reason is :-
There can be only one subtracted numeral, so we can't write IIX for 8. Only I, X, and C can stand before a larger numeral to subtract from it, and they can't stand in front of numerals more than ten times their value; IX for 9 is fine, but we can't write IL for 49 or IM for 1,999 for that we have to write XLIX or MCMXCIX.
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The number 49 in Roman numerals is XLIX and the number 99 in Roman numerals is XCIX
it's XLIX.49 = XLIX
Technically it would be 49, but that is not the way 49 would be written in Roman numerals. It would be stated "IL".
In today's notation of Roman numerals 49 is given as XLIX. But the Romans themselves would have probably notated 49 as IL because it's a simplification of XXXXVIIII.
The number 49 is represented by the Roman numeral XLIX