To check if a number is divisible by another number, we divide.
When we divide, there cannot be a remainder.
For example, is 9 divisible by 3?
Yes, it is because 9 divided by 3 is 3 without a remainder.
How about 4?
No, because when we divide 4 by 3 there is a remainder of 1.
nycfunction@Yahoo.com
sum of the numbers in the given digits should be divisible by 3.then we can say that it is divisible by 3.example :22344 is divisible by 3.since2+2+3+4+4=15.so the given digit is divisible by 3
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A number is divisible by 6 if the number is divisible by 2 AND 3.
All numbers are not divisible by 3. In order to test if a number is a prime, you first test to see if it ends in a 2, 4, 6, 8, or 0. In that case it is divisible by 2 and not a prime. The next number you use for your test is 3. More odd numbers are divisible by 3 than by any other odd number but it is only the second number used for the test. You continue testing until you reach the square root of the number. If the number is only divisible by itself and one, it is prime. 3 is only the second test number in the division test for primes.
Test of divisibility by 2:If a number is even then the number can be evenly divided by 2.5890 is an even number so, it is divisible by 2.Test of divisibility by 3:A number is divisible by 3 if the sum of digits of the number is a multiple of 3.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.So, 5890 is not divisible by 3.Test of divisibility by 6:In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.Test of divisibility by 9:If the sum of digits of a number is divisible by 9 then the number is divisible by 9.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.So, 5890 is not divisible by 9.Test of divisibility by 5:If the last digit of a number is 0 or 5, then it is divisible by 5.It is clear that 5890 is divisible by 5.Test of divisibility by 10:If the last digit of a number is 0, then the number is divisible by 10.It is clear that 5890 is divisible by 10 as the last digit is 0.
No. A good test is to add up the digits of the number (5+3+2) and if that's divisible by three, then the original number is divisible by three.
Test of divisibility by 3:Sum of digits = 1+2+1+5+3 = 12(a multiple of 3)If sum of digits is a multiple of 3 then the number is divisible by 3.So, 12153 is divisible by 3.