How do you apply w equals z plus 1over z to the circle absolute value z equals 2?

Answer 1

To apply the transformation ( w = z + \frac{1}{z} ) to the circle defined by ( |z| = 2 ), we can express ( z ) in polar form as ( z = 2e^{i\theta} ), where ( \theta ) ranges from ( 0 ) to ( 2\pi ). Substituting this into the equation for ( w ), we get ( w = 2e^{i\theta} + \frac{1}{2e^{i\theta}} = 2e^{i\theta} + \frac{1}{2} e^{-i\theta} ). This simplifies to ( w = 2e^{i\theta} + \frac{1}{2}(\cos \theta - i \sin \theta) ), which describes a new curve in the ( w )-plane. The resulting curve can be analyzed further to understand its geometric properties.