Suppose the sides are of length x, y and z units.
Let s = (x + y + z)/2
Then Area = sqrt[s*(s - x)*(s - y)*(s - z)] square units.
Alternatively,
the angle between the lines with lengths y and z is
arccos[(y^2 + z^2 - x^2)/(2*y*z)] = theta, say.
And then area = 0.5*y*z*sin(theta).
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It depends on what information you do have.
The area of any triangle has the same formula, which is base times height, divided by 2. A scalene triangle is a triangle with three sides of unequal length, which is not important when calculating the area.
Area of any triangle: 0.5*base*perpendicular height
................ scalene triangle ................ =)
Yes depending on their dimensions