Interesting one!
If a rectangle has width w and height h,
1) the area a = wh
2) the perimeter p = 2w + 2h
From 1), w=a/h
Substituting into 2)
p = 2a/h + 2h
Multiplying by h
pH = 2a + 2h2
Rearranging
2h2 - pH + 2a = 0 This is a quadratic equation in h.
Factorising, using the standard quadratic formula,
h = (p ± sqrt(p2 - 16a))/4
The two solutions to this will be the two dimensions.
You must first calculate the width, using the formula for the area of a rectangle (plug in the numbers you know into the formula, and solve for width). Once you know this, you can plug in the numbers in the formula for a rectangle's perimeter.
Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm
i dont no if you can find the perimeter of a triagle by using subtration the formula is adding all the up together.
Let the dimensions be x and y:- If: 2x+2y = 29 then y =14.5-x If: xy = 50.3125 then x(14.5-x) = 50.3125 Expanding brackets and transposing terms: 14.5x -x^2 -50.3125 = 0 Using the quadratic equation formula: x = 8.75 or x = 5.75 Therefore dimensions of the rectangle are: length = 8.75 cm and width = 5.75 cm Check: 2(8.75+5.75) = 29 cm Check: 8.75*5.75 = 50.3125 square cm
Perimeter minus two times the width will give you the two times the length. Area is found by multiplying the length by the width.
The shape that has an area of 12 and a perimeter of 16 is a rectangle. To find the dimensions of the rectangle, you can set up equations using the formulas for area and perimeter. Let the length of the rectangle be L and the width be W. The equations would be: 2L + 2W = 16 (perimeter) and LW = 12 (area). Solving these equations simultaneously will give you the dimensions of the rectangle.
You must first calculate the width, using the formula for the area of a rectangle (plug in the numbers you know into the formula, and solve for width). Once you know this, you can plug in the numbers in the formula for a rectangle's perimeter.
The formula for the perimeter of a rectangle is: p = 2(l + w) In other words, just add all four sides. You can't calculate the perimeter of the rectangle if you know only the length.
Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm
By halving its perimeter and using the quadratic equation formula.
i dont no if you can find the perimeter of a triagle by using subtration the formula is adding all the up together.
The new dimensions are 4cm and 7cm
Let x represent width. Using the formula 3x(x)=44cm, the equation is complete when x = 3.82. This means that the rectangle is 3.82 cm wide, and 11.46 cm long.
If the shape is a rectangle (or square), then Perimeter = 2*(Length + Breadth) So Breadth = Perimeter/2 - Length
Yes. But using P=4s is easier with a square.
Not really. All 4 sides of a rectangle are not the same (unless it is a square)
4,3Improved Answer:-The dimensions work out as: 2.358898944 and 6.358898944 inches using the quadratic equation formula