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No it is not correct.
Differing from standard deviations, the coded deviation method finds the mean of grouped data from the assumed mean using unit deviations. This is a shorter way to find the mean.
You cannot because the median of a distribution is not related to its standard deviation.
Did you mean, "How do you calculate the 99.9 % confidence interval to a parameter using the mean and the standard deviation?" ? The parameter is the population mean μ. Let xbar and s denote the sample mean and the sample standard deviation. The formula for a 99.9% confidence limit for μ is xbar - 3.08 s / √n and xbar + 3.08 s / √n where xbar is the sample mean, n the sample size and s the sample standard deviation. 3.08 comes from a Normal probability table.
The variance or standard deviation.