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How do you calculate the amount of CuS and Cu2S in an ore sample given a known sample amount and amount of impurity?
Copper metal can be prepared by roasting copper ore, which can contain cuprite (Cu2S) and Copper (II) sulfide. Cu2S + O2 -> 2Cu + So2
CuS + O2 -> Cu + SO2 Suppose an ore sample contains 11.0% impurity in addition to a mixture of CuS and Cu2S. Heating 100.0 g of the mixture produces 75.4 g of copper metal with a purity of 89.5%. What is the weight percent of CuS in the ore? The weight percent of Cu2S? Clicked enter too fast, sorry.
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