There are many different types of pentagons, and many different ways to calculate the area.
The General CaseAll pentagons can be subdivided into three triangles by drawing two line segments between pairs of pentagon vertices. There are three conditions that must be met when creating the two lines:Given only the information in the question, there is no option but to measure the pentagon at the base and calculate its area.
V = (1/3) (area of the base) (height) Area of a pentagon = 1/2 x apothem length x 5 x length of a side of the pentagonthe apothem is the perpendicular distance from the center of the pentagon to the side of the pentagon
To calculate the square footage of a regular pentagon (where all sides and angles are equal), you can use the formula: ( \text{Area} = \frac{1}{4} \sqrt{5(5 + 2\sqrt{5})} s^2 ), where ( s ) is the length of a side. For an irregular pentagon, you can divide it into simpler shapes (like triangles) to calculate the area of each and then sum them up. Alternatively, you can use the coordinates of the vertices with the shoelace formula if the coordinates are known.
You didn't say it was a regular pentagon. For an arbitrary pentagon, you would calculate its area as you would for any polygon: divide it up into triangles, and add up the areas of the triangle. The area of a triangle is 1/2 times the base times the height, the height being the length of the perpendicular dropped to the base from the opposite vertex.
If 6 is the side of a regular pentagon, the area is 61.937
That depends on the size of the pentagon, and whether it is regular or not. In general, you can divide the pentagon into three triangles, and calculate the area of each triangle separately.
The simplest way is to divide the pentagon into three triangles, calculate the area of each of them and sum the answers.
divide the pentagon into 5 equilateral triangles, and calculate their area. (base times height divided by 2) and when you have your answer, multiply it by 5.
Given only the information in the question, there is no option but to measure the pentagon at the base and calculate its area.
V = (1/3) (area of the base) (height) Area of a pentagon = 1/2 x apothem length x 5 x length of a side of the pentagonthe apothem is the perpendicular distance from the center of the pentagon to the side of the pentagon
To find the area, first divide the shape into regular, simple shapes. Then use formulas to find the area of the smaller, regular shapes. Lastly, add up all the smaller areas to find the area of the original shape.
The area of a pentagon of side length t is given by the formula t2 (sqrt 25 + 10 (sqrt 5)) / 4, or 5t2 tan (54o) / 4. In this case, a pentagon with one side of 10cm has an area of 102 (sqrt 25 + 10 (sqrt 5)) / 4 = 172.05 cm2 (accurate to two decimal places).
To calculate the square footage of a regular pentagon (where all sides and angles are equal), you can use the formula: ( \text{Area} = \frac{1}{4} \sqrt{5(5 + 2\sqrt{5})} s^2 ), where ( s ) is the length of a side. For an irregular pentagon, you can divide it into simpler shapes (like triangles) to calculate the area of each and then sum them up. Alternatively, you can use the coordinates of the vertices with the shoelace formula if the coordinates are known.
You didn't say it was a regular pentagon. For an arbitrary pentagon, you would calculate its area as you would for any polygon: divide it up into triangles, and add up the areas of the triangle. The area of a triangle is 1/2 times the base times the height, the height being the length of the perpendicular dropped to the base from the opposite vertex.
The only general way is to divide the pentagon into three triangles, calculate the areas of the triangles and add them together.
If 6 is the side of a regular pentagon, the area is 61.937
The area (A) formula of a regular pentagon of side length (a) is: A = [a2x(25+10x51/2)1/2]/4 See the why in the development of such formula in the weblink below.