The area of a pentagon of side length t is given by the formula t2 (sqrt 25 + 10 (sqrt 5)) / 4, or 5t2 tan (54o) / 4. In this case, a pentagon with one side of 10cm has an area of 102 (sqrt 25 + 10 (sqrt 5)) / 4 = 172.05 cm2 (accurate to two decimal places).
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∙ 14y agoArea of a regular pentagon with a known side S can be closely approximated by formula 5S2/4 tan 36. Taking 4 tan 36 as 2.906 then the area sought is 2000/2.906 ie 688.23 sq units.
A pentagon has 5 sides. A regular pentagon has sides of all the same length. So a regular pentagon of side 5cm has a perimeter of 5 x 5cm = 25cm.
Pentagon has 5 sides Regular => each side 9cm => perimeter = 5 x 9cm = 45cm
P = 5s, where s is the length of a side. This applies to a regular pentagon. If the pentagon is irregular then P = (s1 + s2 + s3 + s4 + s5)
The area of a regular hexagon with side length of 20cm is about 1039.23cm2
If 6 is the side of a regular pentagon, the area is 61.937
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2
What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
i belive it is 60
386.5
To calculate the area of an irregular pentagon, you can divide it into shapes with known formulas (such as triangles and rectangles) and then sum their areas. Alternatively, you can use a formula specifically designed for irregular pentagons, such as Heron's formula if you know all the side lengths. You may also use trigonometry to calculate the area if you know certain angles and side lengths within the pentagon.
The area (A) formula of a regular pentagon of side length (a) is: A = [a2x(25+10x51/2)1/2]/4 See the why in the development of such formula in the weblink below.
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A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
Area of a regular pentagon with a known side S can be closely approximated by formula 5S2/4 tan 36. Taking 4 tan 36 as 2.906 then the area sought is 2000/2.906 ie 688.23 sq units.
If a pentagon, which is a 5-sided figure, has 26.8 for a perimeter, then each side of that regular pentagon is 26.8 divided by 5 = 5.36 long. How do you get 26.8 for the perimeter of a regular pentagon? Use a regular pentagon with 5.36 for a side length.