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You need to know the speed at which it was fired, which you haven't revealed.

When you have that, here's the procedure:

-- Calculate the horizontal and vertical components of the "launch" speed.

Hint: At 45°, they're both 0.7071 of the launch speed.

Set the horizontal speed aside for later.

-- Take the vertical component of the speed, and calculate how long it would take

a stone, tossed upward at that speed, to hit the ground. The answer is some

number of seconds.

-- Now go back to the horizontal component of speed. Calculate how far a car

or a stone can go at that speed, in the amount of time it took the other stone

to hit the ground.

This whole method makes two important assumptions:

1). No air resistance. The air has no effect on the behavior of the projectile.

2). The ground is flat, and so is the Earth, at least for the distances that

this shot will involve.

At your level in Physics, you would have no chance of solving it without

these assumptions.

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Q: How do you calculate the distance of a projectile fired at a 45 degree angle?
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