You need to know the speed at which it was fired, which you haven't revealed.
When you have that, here's the procedure:
-- Calculate the horizontal and vertical components of the "launch" speed.
Hint: At 45°, they're both 0.7071 of the launch speed.
Set the horizontal speed aside for later.
-- Take the vertical component of the speed, and calculate how long it would take
a stone, tossed upward at that speed, to hit the ground. The answer is some
number of seconds.
-- Now go back to the horizontal component of speed. Calculate how far a car
or a stone can go at that speed, in the amount of time it took the other stone
to hit the ground.
This whole method makes two important assumptions:
1). No air resistance. The air has no effect on the behavior of the projectile.
2). The ground is flat, and so is the Earth, at least for the distances that
this shot will involve.
At your level in Physics, you would have no chance of solving it without
these assumptions.
180 Degree
yes it does. you see if you have it set up at a a 90 degree angle it will go further than it would of a 10 degree angle A projectile leaving the ground at an angle of 45 degrees will attain the maximum range. Fire it straight up and it will fall back to its launch location (wind effects etc. ignored). Fire it horizontally and it will hit the ground very much the same time as if it was dropped from its launch platform at the same time. That would not be very far.
The half maximum range of a projectile is launched at an angle of 15 degree
That depends what you want to calculate.
No. The range of the projectile thrown at 90 degrees is 0. It goes straight up and then straight down!
its 45 degree
The optimal launch angle for the longest distance of a projectile is 45 degrees in the absence of air resistance. This angle allows for the greatest horizontal distance because it balances the vertical and horizontal components of the projectile's velocity.
The weapon should be fired at a 45-degree angle from the horizontal to achieve the minimum distance traveled by the projectile. This angle maximizes the range (horizontal distance) of the projectile by balancing the vertical and horizontal components of its velocity. At any other angle, the total distance traveled would be greater.
180 Degree
yes it does. you see if you have it set up at a a 90 degree angle it will go further than it would of a 10 degree angle A projectile leaving the ground at an angle of 45 degrees will attain the maximum range. Fire it straight up and it will fall back to its launch location (wind effects etc. ignored). Fire it horizontally and it will hit the ground very much the same time as if it was dropped from its launch platform at the same time. That would not be very far.
For the projectile to land at the same distance with the same initial speed, it must be launched at an angle of 15 degrees from the horizontal. This is because the range of a projectile is maximized when launched at a 45-degree angle. So, launching at 15 degrees in the opposite direction of 75 degrees should bring the projectile to the same landing point.
The horizontal distance traveled by a projectile is determined by the initial velocity of the projectile, the angle at which it was launched, and the time of flight. It can be calculated using the equation: horizontal distance = (initial velocity * time * cosine of launch angle).
Release the projectile at a 45 degree angle.
The pull back angle of a catapult affects the distance by determining the trajectory of the projectile. A larger pull back angle typically results in a higher launch angle, which can increase the distance the projectile travels. However, the optimal pull back angle depends on various factors, such as the weight of the projectile and the force of the launch mechanism.
The optimal angle to fire a projectile if the objective is distance is 45 degrees. It follows that the distance traveled decreases whether the angle is increased or decreased from 45.
The half maximum range of a projectile is launched at an angle of 15 degree
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it was launched, and the acceleration due to gravity. Using these values, you can calculate the horizontal distance traveled using the projectile motion equations.