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What is the atomic packing factor of hcp?
.74
How do you calculate the volume of a HCP crystal?
Are you takling Material Science class? Volume of HCP crystal = (a^2) (c) cos30 Im taking Material Science and Engineering
Volume of a HCP unit cell?
The volume of HCP is 8*pi*r^3 or 25.13*r^3
Show that the atomic packing factor for HCP is 0.74?
To answer this question we must look at the HCP itself. We know it is a Hexagonal close packet (HCP) With a CN=12 and common elements are Ti, Mg, Cd etc.Now we have the backup theory, let's answer the question.APF (Atomic packing factor) will equal Vs/Vcwhere Vs is volume of the atoms contained within the unit cell. Vcbeing the volume of total unit cell. Now we look at the structure HCP:Imagine a hexagonal with 6 equilateral triangles contained.Firstly what is Vs? Easy: (volume or sphere?) =4/3(pie)R^3 x 6 (x6 because of 6 spheres per unit cell, remember? HCP has 6 atoms contained)Dissect one equilateral triangle off to work out it's area. The area of this equilateral triangle? Now the side lengths will be a (any value) with 60 degree angles at each edge (total of 180 degrees) therefore the are will be A=ax a x 1/2 x sin(60) =(Sqrt(3) x (a^2)) / 4Now multiply the area of the single triangle by 6 (remember, 6 triangles).Total Area of base of hexagonal =(Sqrt(3) x (3) x a^2) / 2Now remember the formula relating a with R =>a =2RSub R into our base area formula, therefore =6 x Sqrt(3) x R^2 (excluding working out)Now recall the c/a ratio of HCP? c/a=1.63Hence c =1.63 x a > Now sub R (a =2R...)c =3.26 x RNow recall the question? APF? Therefore look back at Vc/Vs, what are we missing? Vc,now Vc=c x base...Vc=3.26 x R x 10.392 x R^2 =33.878 x R^3thereforeAPF =Vs (recall from top working out) / Vc=(8 x (pie) x R^3) / 33.878 x R^3Vc=0.74 ( cancel the R^3)Easy eh? haha
