if g=9.8m/s, G=6.7*10-11Nm2kg-2,calculate the mass of earth, if the radius of the earth is approximately 64m
It's the same as that of Earth but the value of g varies from one object to the other. The value of the gravitational constant or the BIG "G" remains constant. I think you confused it with the LITTLE "g" which is the gravitation of a object (one with mass) or the acceleration due to gravity. The value of g on Earth and Moon is 9.8m/s^2 and 1.6249m/s^2, respectively. I hope this answers you all.
9.8 m/s2 ---------------------- Yes this is the average value of acceleration due to gravity near by the surface of the earth. As we go higher and higher level this g value decreases and becomes almost negligible. Same way as we go deeper and deeper the g value decreases and at the centre of the earth its value becomes zero.
9.8 is the value for g, which stands for Gravity.
On Earth, the gravitational constant, represented by 'g' is 10. To calculate the force in Newtons acting on an object, multiply the mass in kg by 'g'. That would mean said cat weighs 3.72 kg.
Zero.
If the Earth were to stop rotating, the value of 'g' (acceleration due to gravity) would remain approximately the same at the Earth's surface. The rotation of the Earth does not significantly affect the gravitational pull experienced on the surface.
It is -4.62%
if g=9.8m/s, G=6.7*10-11Nm2kg-2,calculate the mass of earth, if the radius of the earth is approximately 64m
The value of 'g' on Pluto is about 0.063 times the value of 'g' on Earth, which is equivalent to about 0.62 m/s^2. This means that gravity on Pluto is much weaker than on Earth.
The value of g is approximately 9.81 m/s^2, representing the acceleration due to gravity on Earth.
The value of g would increase if the compound pendulum is taken nearer to the center of the Earth. This is because gravity is stronger closer to the Earth's surface. Conversely, if the compound pendulum is moved further away from the center of the Earth, the value of g would decrease.
The value of the acceleration due to gravity (g) depends on the mass of the Earth and the distance from its center. As an object moves away from Earth, the value of g will decrease because the gravitational force weakens with distance.
The acceleration due to gravity decreases with distance from the center of the Earth. Using the formula for gravitational acceleration (g) at a distance (r) from the center of the Earth: ( g' = \frac{G \cdot M}{(r+a)^2} ), where a is the radius of the Earth and G is the gravitational constant, you can calculate the distance above the surface of the Earth at which the acceleration due to gravity reduces by 36 percent.
I think that g (the gravitational constant) varies dependent on your proximity to other massive bodies. For example the value of g on the moon is less than the value of g on earth. It is not constant throughout the universe.
It's the same as that of Earth but the value of g varies from one object to the other. The value of the gravitational constant or the BIG "G" remains constant. I think you confused it with the LITTLE "g" which is the gravitation of a object (one with mass) or the acceleration due to gravity. The value of g on Earth and Moon is 9.8m/s^2 and 1.6249m/s^2, respectively. I hope this answers you all.
maybe it is bigger in size than the earth.