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How do you get the value of y intercept in least squares method?
To find the y-intercept, you need to calculate the gradient, b. Then a, the y-intercept, satisfies the equationy-bar = a + b*x-barwhere x-bar and y-bar are the means of the two variables.
What are the control limits for mean and range?
You will need to calculate the grand mean (x double bar) and r bar. From those values and the chart for the constants, all listed in the related link, you will be able to calculate the control limits.
How to calculate surface area of flat bar?
If the bar is a three dimensional object it will have some thickness. Then, assuming it is oblong in shape and knowing its length, width and thickness: Surface_area = 2 x (length x width + width x thickness + thickness x length)
How many one inch cubes are there in a three inch cube?
You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.
How do you calculate angle bar weight?
In order for your to know the weight must know the thickness of the angle bar.
What is the formula to calculate teflon round bar weight?
The formula to calculate the weight of a Teflon round bar is weight = volume x density. First, calculate the volume of the round bar using the formula for the volume of a cylinder: volume = π x (radius)^2 x length. Next, multiply the volume by the density of Teflon to find the weight of the round bar.
How do you get the value of y intercept in least squares method?
To find the y-intercept, you need to calculate the gradient, b. Then a, the y-intercept, satisfies the equationy-bar = a + b*x-barwhere x-bar and y-bar are the means of the two variables.
What are the control limits for mean and range?
You will need to calculate the grand mean (x double bar) and r bar. From those values and the chart for the constants, all listed in the related link, you will be able to calculate the control limits.
How to calculate surface area of flat bar?
If the bar is a three dimensional object it will have some thickness. Then, assuming it is oblong in shape and knowing its length, width and thickness: Surface_area = 2 x (length x width + width x thickness + thickness x length)
Calculate volume of a bar of silver with dimensions 10.0 cm x 6.0 cm x 2.0 cm?
120 cm3 - without using a calculator !
What is formula to calculate the weight of steel bar?
volume of steel multiplied by7850= wt of steel in kgs. Please note that wt of 1 Cum steel is 7850 kg Volume of steel bar can be calculated = cross-sectional area of bar X length cross-sectional area of Bar= pie x d X d/4 (where d is diameter of bar)
Could you help me with this equationA piece of bar is 12mm in diameter calculate the stress in the bar?
Assuming that the bar is made of steel & of circular cross-section & loaded in simple tension, Stress= Load applied/area of the bar. In SI units, area = Pi x (diameter)2/4 "square metre" Apply the load in "Newtons". then calculate the stress developed in N/m2
Calculate the maximum tensile force of steel bar of cross section 20 x 10 with the tensile strength of 400?
80, 20,2,40
What is formula to calculate the area of steel bar?
The formula to calculate the area of a steel bar is A = πr^2, where A represents the area and r is the radius of the steel bar. This formula assumes that the steel bar is circular in shape. If the steel bar is a different shape, such as rectangular or square, the formula to calculate the area would be different based on the dimensions of the bar.
A platinum bar measures 5 cm long 4 cm wide and 1.5 cm thick It has a mass of 700 grams What is the volume?
To calculate the volume of the platinum bar, you can use the formula for the volume of a rectangular prism, which is length x width x height. In this case, the dimensions are 5 cm x 4 cm x 1.5 cm, so the volume would be 30 cubic centimeters.
Gold has a density of 19.3 gcm3 How many grams of gold make up a gold bar that is 20.0 cm x 6.0 cm x 1.0 cm?
To calculate the mass of the gold bar, we first calculate its volume using the formula: Volume = length x width x height. With the dimensions provided, the volume is 20.0 cm x 6.0 cm x 1.0 cm = 120 cm³. Next, we multiply the volume by the density of gold to find the mass: 120 cm³ x 19.3 g/cm³ = 2316 grams. Therefore, a gold bar with dimensions 20.0 cm x 6.0 cm x 1.0 cm would weigh 2316 grams.
How many one inch cubes are there in a three inch cube?
You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.
