You will need to calculate the grand mean (x double bar) and r bar. From those values and the chart for the constants, all listed in the related link, you will be able to calculate the control limits.
To find the y-intercept, you need to calculate the gradient, b. Then a, the y-intercept, satisfies the equationy-bar = a + b*x-barwhere x-bar and y-bar are the means of the two variables.
If the bar is a three dimensional object it will have some thickness. Then, assuming it is oblong in shape and knowing its length, width and thickness: Surface_area = 2 x (length x width + width x thickness + thickness x length)
You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.
In order for your to know the weight must know the thickness of the angle bar.
The formula to calculate the weight of a Teflon round bar is weight = volume x density. First, calculate the volume of the round bar using the formula for the volume of a cylinder: volume = π x (radius)^2 x length. Next, multiply the volume by the density of Teflon to find the weight of the round bar.
You will need to calculate the grand mean (x double bar) and r bar. From those values and the chart for the constants, all listed in the related link, you will be able to calculate the control limits.
To find the y-intercept, you need to calculate the gradient, b. Then a, the y-intercept, satisfies the equationy-bar = a + b*x-barwhere x-bar and y-bar are the means of the two variables.
If the bar is a three dimensional object it will have some thickness. Then, assuming it is oblong in shape and knowing its length, width and thickness: Surface_area = 2 x (length x width + width x thickness + thickness x length)
120 cm3 - without using a calculator !
volume of steel multiplied by7850= wt of steel in kgs. Please note that wt of 1 Cum steel is 7850 kg Volume of steel bar can be calculated = cross-sectional area of bar X length cross-sectional area of Bar= pie x d X d/4 (where d is diameter of bar)
80, 20,2,40
Assuming that the bar is made of steel & of circular cross-section & loaded in simple tension, Stress= Load applied/area of the bar. In SI units, area = Pi x (diameter)2/4 "square metre" Apply the load in "Newtons". then calculate the stress developed in N/m2
To calculate the mass of the gold bar, we first calculate its volume using the formula: Volume = length x width x height. With the dimensions provided, the volume is 20.0 cm x 6.0 cm x 1.0 cm = 120 cm³. Next, we multiply the volume by the density of gold to find the mass: 120 cm³ x 19.3 g/cm³ = 2316 grams. Therefore, a gold bar with dimensions 20.0 cm x 6.0 cm x 1.0 cm would weigh 2316 grams.
You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.
Volume = area x depth. Area = width x length There are various sizes of Hershey bars, so you'll have to calculate the answer to your homework question yourself. :) Measure the width and length of the candy bar, and multiply those two numbers tomget the area. Measure the depth of the candy bar, and multiply that number by the area, and that will give you the volume.
It is probably easiest to measure rather than calculate it. What you are looking for is simply the length of the bar, expressed in metres.