To find the y-intercept, you need to calculate the gradient, b. Then a, the y-intercept, satisfies the equationy-bar = a + b*x-barwhere x-bar and y-bar are the means of the two variables.
You will need to calculate the grand mean (x double bar) and r bar. From those values and the chart for the constants, all listed in the related link, you will be able to calculate the control limits.
If the bar is a three dimensional object it will have some thickness. Then, assuming it is oblong in shape and knowing its length, width and thickness: Surface_area = 2 x (length x width + width x thickness + thickness x length)
You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.
X-bar represents the mean or average of the sample variable.
The formula to calculate the weight of a Teflon round bar is weight = volume x density. First, calculate the volume of the round bar using the formula for the volume of a cylinder: volume = π x (radius)^2 x length. Next, multiply the volume by the density of Teflon to find the weight of the round bar.
To find the y-intercept, you need to calculate the gradient, b. Then a, the y-intercept, satisfies the equationy-bar = a + b*x-barwhere x-bar and y-bar are the means of the two variables.
You will need to calculate the grand mean (x double bar) and r bar. From those values and the chart for the constants, all listed in the related link, you will be able to calculate the control limits.
If the bar is a three dimensional object it will have some thickness. Then, assuming it is oblong in shape and knowing its length, width and thickness: Surface_area = 2 x (length x width + width x thickness + thickness x length)
120 cm3 - without using a calculator !
volume of steel multiplied by7850= wt of steel in kgs. Please note that wt of 1 Cum steel is 7850 kg Volume of steel bar can be calculated = cross-sectional area of bar X length cross-sectional area of Bar= pie x d X d/4 (where d is diameter of bar)
80, 20,2,40
Assuming that the bar is made of steel & of circular cross-section & loaded in simple tension, Stress= Load applied/area of the bar. In SI units, area = Pi x (diameter)2/4 "square metre" Apply the load in "Newtons". then calculate the stress developed in N/m2
To calculate the volume of the platinum bar, you can use the formula for the volume of a rectangular prism, which is length x width x height. In this case, the dimensions are 5 cm x 4 cm x 1.5 cm, so the volume would be 30 cubic centimeters.
To calculate the mass of the gold bar, we first calculate its volume using the formula: Volume = length x width x height. With the dimensions provided, the volume is 20.0 cm x 6.0 cm x 1.0 cm = 120 cm³. Next, we multiply the volume by the density of gold to find the mass: 120 cm³ x 19.3 g/cm³ = 2316 grams. Therefore, a gold bar with dimensions 20.0 cm x 6.0 cm x 1.0 cm would weigh 2316 grams.
You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.You calculate this as 3 x 3 x 3 = 27.
The formula to calculate the area of a steel bar is A = πr^2, where A represents the area and r is the radius of the steel bar. This formula assumes that the steel bar is circular in shape. If the steel bar is a different shape, such as rectangular or square, the formula to calculate the area would be different based on the dimensions of the bar.