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How do you calculate the parameter to a 99.9 confidence interval using mean and standard deviation?
Did you mean, "How do you calculate the 99.9 % confidence interval to a parameter using the mean and the standard deviation?" ? The parameter is the population mean μ. Let xbar and s denote the sample mean and the sample standard deviation. The formula for a 99.9% confidence limit for μ is xbar - 3.08 s / √n and xbar + 3.08 s / √n where xbar is the sample mean, n the sample size and s the sample standard deviation. 3.08 comes from a Normal probability table.
What is the Formula for sample deviation?
I believe you want the equation to calculate the standard deviation of a sample. The equation is: s = square root[ sum from i =1 to n of (xi- xbar)/(n-1)] where xbar is the average of values of the sample and n = size of sample.
Difference between estimate estimator?
I think, the estimate is a numerical value, wile the estimator is a function or operator, which can be generate more estimates according to some factors. For example (xbar) is estimator for (meu), which can be various when the sample size in various, the value that will be produced is an (estimate), but (xbar) is estimator.
Consider a population with a mean of 63.3 and a standard deviation of 3.82 and a score of 61.6. Calculate the z-score for 61.6 from a sample of size 19?
Mean μ = 63.3 Standard deviation σ = 3.82 Standard error σ / √ n = 3.82 / √ 19 = 0.8763681 z = (xbar - μ) / (σ / √ n ) z = (61.6-63.3) / 0.876368 z = -1.9398
What is the T-Test formula?
t= absolute value of ( sample 1 - sample two) THEN DIVIDED by the (standard error of sample one - standard error of sample 2) standard error = the standard deviation divided by (square root of the pop. sample number) You have to work in steps to get all info 1. mean ( REPRESENTED BY 'Xbar') 2. sum of squares ('SS') 3. Sample variance ('s^2') 4. standard deviation ('s') 5. standard error ('s subscript x') 6. pooled measure ('s^2p') 7. Standard error between means (s subscript mean one-mean two) 8. t test In other word finding the mean and having ht esample info leads you to each formula with the end formular being the t-test have fun, its easy but dumb
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Can any set of normally distributed data be transformed to its standarized form?
Yes. The transform is z= (x-xbar)/s where x is the data value, xbar is the mean of the data and s is the standard deviation.
How do you calculate the parameter to a 99.9 confidence interval using mean and standard deviation?
Did you mean, "How do you calculate the 99.9 % confidence interval to a parameter using the mean and the standard deviation?" ? The parameter is the population mean μ. Let xbar and s denote the sample mean and the sample standard deviation. The formula for a 99.9% confidence limit for μ is xbar - 3.08 s / √n and xbar + 3.08 s / √n where xbar is the sample mean, n the sample size and s the sample standard deviation. 3.08 comes from a Normal probability table.
What is the Formula for sample deviation?
I believe you want the equation to calculate the standard deviation of a sample. The equation is: s = square root[ sum from i =1 to n of (xi- xbar)/(n-1)] where xbar is the average of values of the sample and n = size of sample.
Difference between estimate estimator?
I think, the estimate is a numerical value, wile the estimator is a function or operator, which can be generate more estimates according to some factors. For example (xbar) is estimator for (meu), which can be various when the sample size in various, the value that will be produced is an (estimate), but (xbar) is estimator.
Formula for z-test?
The z score is calculated from the distance of a value from the distribution center divided by the standard dev. (x-xbar)/st. dev
What biased estimator will have a reduced bias based on an increased sample size?
The standard deviation. There are many, and it's easy to construct one. The mean of a sample from a normal population is an unbiased estimator of the population mean. Let me call the sample mean xbar. If the sample size is n then n * xbar / ( n + 1 ) is a biased estimator of the mean with the property that its bias becomes smaller as the sample size rises.
Is any idea for java code writing linear regression?
import java.io.*;import java.util.*;public class LinearRegression {public static void main(String[] args) {int MAXN = 1000;int n = 0;double[] x = new double[MAXN];double[] y = new double[MAXN];// first pass: read in data, compute xbar and ybardouble sumx = 0.0, sumy = 0.0, sumx2 = 0.0;while(!StdIn.isEmpty()) {x[n] = StdIn.readDouble();y[n] = StdIn.readDouble();sumx += x[n];sumx2 += x[n] * x[n];sumy += y[n];n++;}double xbar = sumx / n;double ybar = sumy / n;// second pass: compute summary statisticsdouble xxbar = 0.0, yybar = 0.0, xybar = 0.0;for (int i = 0; i < n; i++) {xxbar += (x[i] - xbar) * (x[i] - xbar);yybar += (y[i] - ybar) * (y[i] - ybar);xybar += (x[i] - xbar) * (y[i] - ybar);}double beta1 = xybar / xxbar;double beta0 = ybar - beta1 * xbar;// print resultsSystem.out.println("y = " + beta1 + " * x + " + beta0);// analyze resultsint df = n - 2;double rss = 0.0; // residual sum of squaresdouble ssr = 0.0; // regression sum of squaresfor (int i = 0; i < n; i++) {double fit = beta1*x[i] + beta0;rss += (fit - y[i]) * (fit - y[i]);ssr += (fit - ybar) * (fit - ybar);}double R2 = ssr / yybar;double svar = rss / df;double svar1 = svar / xxbar;double svar0 = svar/n + xbar*xbar*svar1;System.out.println("R^2 = " + R2);System.out.println("std error of beta_1 = " + Math.sqrt(svar1));System.out.println("std error of beta_0 = " + Math.sqrt(svar0));svar0 = svar * sumx2 / (n * xxbar);System.out.println("std error of beta_0 = " + Math.sqrt(svar0));System.out.println("SSTO = " + yybar);System.out.println("SSE = " + rss);System.out.println("SSR = " + ssr);}}
What does a x with a line over it mean?
The symbol for the arithmetic mean (average) of a group of numbers. The pronunciation is 'x bar'. If the set of numbers can be represented by (2, 3, 4, 4, 5), then the mean = (2+ 3+ 4+ 4+ 5)/5 = 3.6. So xbar = 3.6.
How the formula of z obtained?
The formula for Z obtained is zobt equals the average of the sample (Xbar)minus the average of the population (u), divided b the standard deviation of the sample (s), divided be the square root of N. Example: Zobt= X-u ,divided by s ,divided by ,square root of N
Formula for s in statistics?
s=sample standard deviation s=square root (Sum(x-(xbar))2 /(n-1) Computing formula (so you don't have to find the mean and the distance from the mean over and over): square root(Sxx /(n-1)) Sxx= Sum(x2) - ((Sum(x))2/n)
If you select a large enough sample size can you reject any null hypothesis?
The simple answer is no. This depends on a lot of factors such as alpha which determines the critical value and the absolute value of the difference between the claim and sample data. Mathematically speaking, all things being equal, the larger the sample size the larger the absolute value of the test statistic. The formula for the test statistic mean with sigma known is shown below. You can substitute values in and perform the mathematics. The larger the sample size, the larger the Z value; but note if the numerator is small, even a small denominator will not produce a large Z value. In fact, the numerator could be zero which would make the test statistic zero. Z = (Xbar - μxbar)/(σ/√n) (formula from Elementary Statistics by Mario F. Triola)
