Q: How do you calculate this sum 18-2x3 plus 1?

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The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1

Sum = 79*(79+1)/2 = 79*80/2 = 3160

The sum of -1 and -1 is -2.

1+0+3 is the digit sum of 103

Three ways.. Multiply n by itself. Calculate Sum[2i+1,{i,0,n-1}] Calculate Sum[n,{i,1,n}]

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The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1

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if (n%2==0) sum=n/2*(n+1); else sum=(n+1)/2*n;

Sum = 79*(79+1)/2 = 79*80/2 = 3160

The sum of -1 and -1 is -2.

1+0+3 is the digit sum of 103