Q: How do you find the sum of 1 plus 2 plus 3 plus 4 plus . plus 79?

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8/9

The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1

It is simply: 1/79

The sum of -1 and -1 is -2.

1+0+3 is the digit sum of 103

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if (n%2==0) sum=n/2*(n+1); else sum=(n+1)/2*n;

78 + 1 = 79

8/9

The answer would be positive 3.

the sum of 1 plus 9 is 10 because 1+9

(xn+2-1)/(x2-1)

80

0

3x2 + 2x + 3 + x2 + x + 1 = 4x 2+ 3x + 4

The sum is: 8

The sum is 1511.

The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1