divide the beam into three rectangles, calculate the area of each rectangle and multiply it by length. then you get the volume of beam & finally multiply it by density
150*150*10thk h beam weight per meter
It is not possible to calculate the area given only the volume.
You cannot calculate volume of surface area. If you meant 20m3, then the volume would be 20,000 litres.
Not enough information. To calculate mass, you would need volume and density (mass = volume x density).
V=Area*Length
To calculate the total volume of a beam, we need to know its cross-sectional shape (e.g. rectangular, circular) and dimensions. If the beam is a rectangular prism with a cross-section of 1ft x 1ft, then the volume would be 60 cubic feet. If the cross-section is different, we need that information to calculate the volume.
To calculate the self weight of a beam, you need to determine the volume of the beam (length x width x height) and then multiply this by the density of the material the beam is made of. The density value can vary depending on the material used. Finally, multiply the volume by the density to find the self weight of the beam.
divide the beam into three rectangles, calculate the area of each rectangle and multiply it by length. then you get the volume of beam & finally multiply it by density
For mass you use a triple-beam balance and for volume you use a graduated cylinder
You can consider the beam to be a rectangular block. In other words, simply multiply length x width x height.
For mass, you would use a triple-beam balance. For volume, you would either use a graduated cylinder (for liquids), calculate the displacement with a graduated cylinder (for an odd-shaped solid), or calculate it using the equation for volume (for a regularly-shaped solid).
Depends on the dimensions of the beam. length * width * height
No, a triple balance beam will measure the mass of an object but not its volume.
Calculate the volume of one sweet. Calculate the volume of the jar and then divide the volume of the jar by the volume of a sweet.
the beam has a total volume of 60ft 3 what is the maximium horizontal gap that the beam can span
get dearer