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Here are the steps:
ax^2 + bx + c = 0 Subtract c and divide by a
x^2 + (b/a)x = -(c/a) Take the square of (b/a)/2 and add it to both sides
(x + ((b/a)/2))^2 = -(c/a) + ((b/a)/2)^2 Take the square root of both sides
Subtract ((b/a)/2) and you have your solutions:
x = -(c/a) + ((b/a)/2)^2 - ((b/a)/2)
x = (c/a) - ((b/a)/2)^2 - ((b/a)/2)
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No, they cannot. Sorry! Hope I helped you figure out your math problem!
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It often helps to take square roots on both sides of the equation. However, solutions to the original equation may be lost - it is often convenient to put a "plus or minus" sign so as not to lose solutions. Example: x2 = 25 Taking square roots: x = "plus or minus" 5
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a polygon,quadrilateral,parallelogram,rectangle and a rhombus hope this helps if you are having a problem with math
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The product is the "sum" of a multiplication math problem.
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