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To completely factor the expression (2x^2 - 8), first factor out the greatest common factor, which is 2. This gives you (2(x^2 - 4)). Next, recognize that (x^2 - 4) is a difference of squares, which can be factored further as ((x - 2)(x + 2)). Therefore, the complete factorization is (2(x - 2)(x + 2)).
What else can I help you with?
Factor 2x squared plus x - 6?
8
How do you factor 2x squared minus 16?
2(x^2 - 8)
How do you factor 6x squared minus 7x minus 24?
It is: (2x+3)(3x-8) when factored
Factor Completely x3 plus 8?
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
Factor completely and check mentally 40n squared plus 64n?
8n(5n+8)
Factor 2x squared plus x - 6?
8
How do you factor 2x squared minus 16?
2(x^2 - 8)
How do you factor 10x squared plus 11x minus 8?
(2x - 1)(5x + 8)
How do you factor x squared minus 2x minus 8?
(x + 2)(x - 4)
How do you factor 6x squared minus 7x minus 24?
It is: (2x+3)(3x-8) when factored
Factor Completely x3 plus 8?
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
Factor completely and check mentally 40n squared plus 64n?
8n(5n+8)
Factor completely xy - 2x plus 4y -8?
xy-2x+4y-8 x(y-2)+4(y-2) (x+4)(y-2)
Factor 8x squared - 16x plus 8?
8x2-16x+8=8(x-1)2 How to do it: First factor out the 8 and you have 8(x2 -2x+1) look at the 1 and not the only two way to get 1 are by multiplying -1x-1 or 1x1 Only the -1x-1 will work and give us the -2x.
What is the solution to 3x squared -2x-8?
3x2-2x-8 = (3x+4)(x-2) when factored
How do you factor 8 x squared minus ten x minus three?
8x2-10x-3 = (2x-3)(4x+1) when factored
Fx 2x plus 1 over x squared minus 2x minus 8?
5x lolzz 8)
