8
2(x^2 - 8)
It is: (2x+3)(3x-8) when factored
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
8n(5n+8)
8
2(x^2 - 8)
(2x - 1)(5x + 8)
(x + 2)(x - 4)
It is: (2x+3)(3x-8) when factored
To solve the expression 8x^2 * 2x, you first multiply the coefficients (8 * 2 = 16). Then, you multiply the variables with the same base by adding their exponents (x^2 * x = x^(2+1) = x^3). Therefore, the simplified expression is 16x^3.
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
8n(5n+8)
xy-2x+4y-8 x(y-2)+4(y-2) (x+4)(y-2)
8x2-16x+8=8(x-1)2 How to do it: First factor out the 8 and you have 8(x2 -2x+1) look at the 1 and not the only two way to get 1 are by multiplying -1x-1 or 1x1 Only the -1x-1 will work and give us the -2x.
3x2-2x-8 = (3x+4)(x-2) when factored
8x2-10x-3 = (2x-3)(4x+1) when factored