It is called a bisector.
Theorem: The line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side. Proof: Consider the triangle ABC with the midpoint of AB labelled M. Now construct a line through M parallel to BC.
With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.
it gives you the midpoint of the line segment you use the formula for
A midpoint of anything is the point exactly halfway between the beginning point and the end point. So logically, it is the "midpoint".
the median is drawn from the vertex to the midpoint of the opposite side
Perpendicular Bisector
A segment bisector
It is called a bisector.
A perpendicular bisector.
the endpoints lie on each other
Because both lines and rays are infinite in length and thus have no midpoint.
Such a line is called a perpendicular bisector.
Definition of angle bisector:An angle is formed by two rays with a common endpoint. The angle bisector is a ray or line segment that bisects the angle, creating two congruent angles. To construct an angle bisector you need a compass and straightedge.Definition of midpoint:Midpoint of a line segment is the point that is halfway between the endpoints of the line segment. A line segment has only one midpoint. If AB is a line segment and P is the midpoint, then AP = BP =
First you need a compass.Given: You need to create a ray that makes 2 congruent angles.Given Angle ABC, carry out the following steps to construct the angle bisector.Step 1: Construct a circle with center at B. Label the points F and G where the circle intersects the angle.Step 2: Construct two intersecting circles of equal radii at the points F and G. Label their intersection points K and L.Step 3: Construct Ray BKYou're done! Ray BK bisects Angle ABC.It's a little confusing so it make be easier if you just wanted the video with the drawing.
Theorem: The line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side. Proof: Consider the triangle ABC with the midpoint of AB labelled M. Now construct a line through M parallel to BC.
With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.