Divide 713 by 5, and the remainder in that division is the Units (50) digit. Take the quotient (without the remainder) and divide by 5. The remainder in this division is the Fives (51) digit. Continue dividing until the quotient is less tan 5 and that digit will be the leftmost digit.
713/5 = 142 and rem 3 so 50 digit = 3
142/5 = 28 and rem 2 so 51 digit = 2
28/5 = 5 and rem 3 so 52 digit = 3
5/5 = 1 and rem 0 so 53 digit = 0
and last quotient, 1 < 5 so stop with leftmost digit = 1.
Then 71310 = 103235
Convert the base 10 numeral to a numeral in the base indicated. 503 to base 5
To convert a number from base 10 to base 5, repeatedly divide the number by 5 and record the remainders. Start with the original number, divide it by 5, and note the remainder; this remainder is the least significant digit in base 5. Continue dividing the quotient by 5 until the quotient reaches zero, then read the remainders in reverse order to get the base 5 representation. For example, to convert 25 to base 5, you would divide it by 5 to get 5 (remainder 0), then divide 5 by 5 to get 1 (remainder 0), and finally divide 1 by 5 to get 0 (remainder 1), resulting in 100 in base 5.
Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.
1225 = 1 x 52 + 2 x 5 + 2 = 3710
To convert the decimal number 23 to base 5, we divide the number by 5 and keep track of the remainders. Dividing 23 by 5 gives a quotient of 4 and a remainder of 3. Next, dividing the quotient 4 by 5 gives a quotient of 0 and a remainder of 4. Reading the remainders from bottom to top, 23 in base 5 is represented as 43.
Convert the base 10 numeral to a numeral in the base indicated. 503 to base 5
To convert a number from base 10 to base 5, repeatedly divide the number by 5 and record the remainders. Start with the original number, divide it by 5, and note the remainder; this remainder is the least significant digit in base 5. Continue dividing the quotient by 5 until the quotient reaches zero, then read the remainders in reverse order to get the base 5 representation. For example, to convert 25 to base 5, you would divide it by 5 to get 5 (remainder 0), then divide 5 by 5 to get 1 (remainder 0), and finally divide 1 by 5 to get 0 (remainder 1), resulting in 100 in base 5.
Since 52 = 25, and twice 25 is 50, the answer is 200.
To add two numbers in different bases, we first convert them to the same base. In this case, we convert 43 base 5 to base 10, which is 23. Then we convert 24 base 5 to base 10, which is 14. Adding 23 and 14 in base 10 gives us 37. Finally, we convert 37 back to base 5, which is 112. So, 43 base 5 plus 24 base 5 equals 112 base 5.
To convert a number from base 5 to base 10, you multiply each digit by 5 raised to the power of its position from the right, starting at 0. In this case, for the number 43 base 5, you would calculate (4 * 5^1) + (3 * 5^0) = (4 * 5) + (3 * 1) = 20 + 3 = 23 base 10. Thus, 43 base 5 is equal to 23 base 10.
142120
Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.
708
1225 = 1 x 52 + 2 x 5 + 2 = 3710
To convert the decimal number 23 to base 5, we divide the number by 5 and keep track of the remainders. Dividing 23 by 5 gives a quotient of 4 and a remainder of 3. Next, dividing the quotient 4 by 5 gives a quotient of 0 and a remainder of 4. Reading the remainders from bottom to top, 23 in base 5 is represented as 43.
To convert the number 210 from base 5 to base 10, you calculate it as follows: (2 \times 5^2 + 1 \times 5^1 + 0 \times 5^0). This equals (2 \times 25 + 1 \times 5 + 0 \times 1), which simplifies to (50 + 5 + 0 = 55). Therefore, 210 in base 5 is 55 in base 10.
To convert the number (131_5) from base 5 to base 10, you multiply each digit by (5) raised to the power of its position, starting from the right (position 0). So, (1 \times 5^2 + 3 \times 5^1 + 1 \times 5^0) equals (1 \times 25 + 3 \times 5 + 1 \times 1), which simplifies to (25 + 15 + 1 = 41). Therefore, (131_5) in base 10 is (41).