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Convert 2.5g mL to the unit g L?
2.5 g per mL = 2,500 g per Litre.
What is the value of x When a 1.63 g sample of MgCl2xH2O is heated to remove all water a mass of 0.762 g remains?
You begin with 1.63 g of MgCl2•xH2O. You end up with 0.762 g MgCl2. That means you lost 1.63 - 0.762 = 0.87 g of H2O. 0.762 g MgCl2 / 95.21 g (molar mass) = .00800 mol MgCl2 0.87 g H2O / 18.02 g (molar mass) = .048 mol H2O x = mol solute / mol solvent x = .048 mol H2O / .00800 mol MgCl2 x = 6 MgCl2•6H2O
How many milligrams of sodium make one gram of salt?
Formula for table salt = NaCl 1.00 g = 1.00 / 58.45 mol = 1.71 x 10-2 mol Mole Na required = 1.71 x 10-2 mol Mass of Na = 1.71 x 10-2 mol x 23.0 g /mol = 0.393 g = 393 mg
What is the molarity of a solution that contains 0.65 moles of NaNO3 in 250 mL of solution?
Molarity (M) = moles of solute (mol) / liter of solution (L)M = mol / LYou have 250 mL of Solution, which is250 mL x ( 1 L / 1000 mL ) = ( 250 / 1000 ) L = .25 LSolute is just what's dissolvedSolvent is just what it's being dissolved inSolution is the solute and the solvent.M = mol / LM = 0.65 mol / 0.25 Liters = 2.6 mol/LThe two numbers that you are given, 0.65 moles and 250 mL both have two significant figures, and the answer is two significant figures (2.6 mol/L)Therefore the answer is 2.6 mol/L.
What is the gas constant?
8.31 L-kPa/mol-K
What is the molarity of a 0.142 M Na3 PO4 solution that has a density of 1.015 g m L Show all the steps?
To find the molarity of the Na3PO4 solution, we first need to calculate the molar mass of Na3PO4: Na: 22.99 g/mol P: 30.97 g/mol O: 16.00 g/mol Total molar mass = 22.99 * 3 + 30.97 + 16.00 * 4 = 163.94 g/mol Next, we find the concentration in mol/L: 0.142 M Na3PO4 = 0.142 mol/L Then, we convert the density from g/mL to g/L: 1.015 g/mL * 1000 mL/L = 1015 g/L Finally, we calculate the molarity using the formula: molarity = (density / molar mass) * concentration molarity = (1015 g/L / 163.94 g/mol) * 0.142 mol/L ≈ 0.88 M
How many grams of ammonia are presented in 5.0 l of a 0.050 m solution?
To find the grams of ammonia present, first calculate the moles of ammonia in the solution using the molarity formula (moles = molarity x volume). Then, convert moles to grams using the molar mass of ammonia (NH3 is 17.03 g/mol). Therefore, in a 5.0 L 0.050 M solution, there would be 4.26 grams of ammonia present.
What would be useful for converting g mol to g L?
Molarity
What is the molarity of 930 mL of LiCl solution that contains 139.9 g of LiCl?
To calculate the molarity, first convert the mass of LiCl to moles using its molar mass (6.94 g/mol for Li, 35.45 g/mol for Cl). Then, divide the moles of LiCl by the volume in liters (930 mL = 0.93 L) to get the molarity. The molarity of the solution would be around 5.2 mol/L.
How many grams of iodine would you weigh out to prepare 50 mL of a 0.200 N iodine solution?
To calculate the mass of iodine needed to prepare a 0.200 N solution in 50 mL, you can use the formula: Mass (g) = molarity (mol/L) * volume (L) * molar mass (g/mol). First, convert 50 mL to L (50 mL = 0.050 L). Then, substitute the values: Mass (g) = 0.200 mol/L * 0.050 L * 253.8 g/mol = 2.538 g of iodine. Therefore, you would weigh out 2.538 grams of iodine.
How do you convert gmol to gl?
mol/L
What is the formula to convert gm to mmol per liter?
To convert grams (g) to millimoles per liter (mmol/L) for a substance, you need to know the molar mass of the substance. Then you can use the formula: Concentration in mmol/L = (mass in g) / (molar mass in g/mol) * 1000.
A measure of salts in the water is?
Examples are: mol/L, g/L, g/1oo mL.
What is the molarity of a solution in which 58 g of NaCl are dissolved in 1.0 L of solution?
The molar mass of NaCl is 58.44 g/mol. To calculate the molarity, first convert grams to moles (58 g / 58.44 g/mol = 0.993 mol). Then divide moles by liters of solution (0.993 mol / 1.0 L = 0.993 M). Therefore, the molarity of the solution is 0.993 M.
How many grams of KBr are required to make 750.0 mL of solution that is 0.0552M molar mass of KBr 119.00gmol?
To calculate the mass of KBr needed, first determine the moles of KBr required using the formula: moles = Molarity x Volume (in liters). Then, convert moles to grams using the molar mass of KBr: mass = moles x molar mass. In this case, 0.0552M x 0.750 L = 0.0414 moles of KBr needed, which is equivalent to 4.93 grams of KBr.
How many grams of solute are in the following solutions 4.5 L of 3.0 M AlNO3 3?
To find the grams of solute, first calculate the moles of AlNO3 3 using the molarity (3.0 M) and volume (4.5 L). Then, use the molar mass of AlNO3 3 (212.99 g/mol) to convert moles to grams. The calculation would be: (3.0 mol/L) * (4.5 L) * (212.99 g/mol) = 285.87 g of AlNO3 3.
What mass of H2SO4is contained in 60.00 mL of a 5.85 M solution of sulfuric acid?
To calculate the mass of H2SO4, you first find the moles of H2SO4 using the molarity formula (moles = molarity x volume). Then use the molar mass of H2SO4 (98.08 g/mol) to convert moles to grams. Given that the solution is 5.85 M, you would first calculate moles of H2SO4: 5.85 mol/L x 0.060 L = 0.351 mol. Then convert moles to grams: 0.351 mol x 98.08 g/mol ≈ 34.44 grams of H2SO4.
