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Convert 2.5g mL to the unit g L?
2.5 g per mL = 2,500 g per Litre.
How many grams of LiCl are required to make 2.0 of 0.65?
To calculate the grams of LiCl needed to make a 2.0 L solution at a concentration of 0.65 M, use the formula: [ \text{grams of solute} = \text{molarity} \times \text{volume (L)} \times \text{molar mass} ] The molar mass of LiCl is approximately 42.39 g/mol. Thus: [ \text{grams of LiCl} = 0.65 , \text{mol/L} \times 2.0 , \text{L} \times 42.39 , \text{g/mol} \approx 55.85 , \text{g} ] Therefore, approximately 55.85 grams of LiCl are required.
What is the value of x When a 1.63 g sample of MgCl2xH2O is heated to remove all water a mass of 0.762 g remains?
You begin with 1.63 g of MgCl2•xH2O. You end up with 0.762 g MgCl2. That means you lost 1.63 - 0.762 = 0.87 g of H2O. 0.762 g MgCl2 / 95.21 g (molar mass) = .00800 mol MgCl2 0.87 g H2O / 18.02 g (molar mass) = .048 mol H2O x = mol solute / mol solvent x = .048 mol H2O / .00800 mol MgCl2 x = 6 MgCl2•6H2O
What is the value of G at 500 K if H27kJMol and S0.09kJ(molK)?
To find the Gibbs free energy change (ΔG) at 500 K, we can use the equation ΔG = ΔH - TΔS. Given that ΔH = -27 kJ/mol and ΔS = 0.09 kJ/(mol·K), we first convert the temperature to Kelvin (which is already given as 500 K). Then, substituting the values: ΔG = -27 kJ/mol - (500 K × 0.09 kJ/(mol·K)) = -27 kJ/mol - 45 kJ/mol = -72 kJ/mol. Thus, the value of G at 500 K is -72 kJ/mol.
How many grams are in 8.2 x 1022 molecules f N2l6?
To find the mass in grams of 8.2 x 10^22 molecules of N2l6, we first need to determine the molar mass of N2l6. The molar mass is calculated by adding the atomic masses of nitrogen (N) and iodine (l) in the formula. N has an atomic mass of approximately 14 g/mol and I has about 127 g/mol; thus, N2l6 has a molar mass of (2 * 14) + (6 * 127) = 868 g/mol. Next, we convert the number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol): 8.2 x 10^22 molecules * (1 mol / 6.022 x 10^23 molecules) ≈ 0.136 moles. Finally, we multiply the number of moles by the molar mass: 0.136 moles * 868 g/mol ≈ 118.5 grams. Therefore, there are approximately 118.5 grams of N2l6 in 8.2 x 10^22 molecules.
What is the molarity of a 0.142 M Na3 PO4 solution that has a density of 1.015 g m L Show all the steps?
To find the molarity of the Na3PO4 solution, we first need to calculate the molar mass of Na3PO4: Na: 22.99 g/mol P: 30.97 g/mol O: 16.00 g/mol Total molar mass = 22.99 * 3 + 30.97 + 16.00 * 4 = 163.94 g/mol Next, we find the concentration in mol/L: 0.142 M Na3PO4 = 0.142 mol/L Then, we convert the density from g/mL to g/L: 1.015 g/mL * 1000 mL/L = 1015 g/L Finally, we calculate the molarity using the formula: molarity = (density / molar mass) * concentration molarity = (1015 g/L / 163.94 g/mol) * 0.142 mol/L ≈ 0.88 M
How to calculate concentration from molarity?
To calculate concentration from molarity, you can use the formula: concentration (in g/L) molarity (in mol/L) x molar mass (in g/mol). This formula helps you convert the molarity of a solution into its concentration in grams per liter.
How many grams of ammonia are presented in 5.0 l of a 0.050 m solution?
4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g
What would be useful for converting g mol to g L?
Molarity
What is the molarity of 930 mL of LiCl solution that contains 139.9 g of LiCl?
To calculate the molarity, first convert the mass of LiCl to moles using its molar mass (6.94 g/mol for Li, 35.45 g/mol for Cl). Then, divide the moles of LiCl by the volume in liters (930 mL = 0.93 L) to get the molarity. The molarity of the solution would be around 5.2 mol/L.
How do you convert gmol to gl?
mol/L
How many grams of iodine would you weigh out to prepare 50 mL of a 0.200 N iodine solution?
To calculate the mass of iodine needed to prepare a 0.200 N solution in 50 mL, you can use the formula: Mass (g) = molarity (mol/L) * volume (L) * molar mass (g/mol). First, convert 50 mL to L (50 mL = 0.050 L). Then, substitute the values: Mass (g) = 0.200 mol/L * 0.050 L * 253.8 g/mol = 2.538 g of iodine. Therefore, you would weigh out 2.538 grams of iodine.
What is the formula to convert gm to mmol per liter?
To convert grams (g) to millimoles per liter (mmol/L) for a substance, you need to know the molar mass of the substance. Then you can use the formula: Concentration in mmol/L = (mass in g) / (molar mass in g/mol) * 1000.
What is the conversion factor to convert daltons (Da) to grams per mole (g/mol)?
The conversion factor to convert daltons (Da) to grams per mole (g/mol) is 1 Da 1.66054 x 10-24 g/mol.
A measure of salts in the water is?
Examples are: mol/L, g/L, g/1oo mL.
What is the molarity of a solution in which 58 g of NaCl are dissolved in 1.0 L of solution?
The molar mass of NaCl is 58.44 g/mol. To calculate the molarity, first convert grams to moles (58 g / 58.44 g/mol = 0.993 mol). Then divide moles by liters of solution (0.993 mol / 1.0 L = 0.993 M). Therefore, the molarity of the solution is 0.993 M.
How many grams of KBr are required to make 750.0 mL of solution that is 0.0552M molar mass of KBr 119.00gmol?
Multiply the molarity (M, which is in mol/L) with the volume (in L) to get the number of moles needed. Then multiply the result with the molar mass. If you look at the units they will cancel to give an answer in grams. (mol/L)*(L)=mol, (mol)*(g/mol)=g So for the numerical answer you get (0.0552 mol/L)*(0.750 L)*(119.00 g/mol)= 4.93 g KBr
