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Do you have a specific vertex fraction? vertex = -b/2a wuadratic = ax^ + bx + c
You use standard form in algebra because you have to know the number before you answer the problem
Well, if we're talking algebra, then standard form is ax+by=c
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
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y= -5/49(x-9)^2+5
The difference between standard form and vertex form is the standard form gives the coefficients(a,b,c) of the different powers of x. The vertex form gives the vertex 9hk) of the parabola as part of the equation.
Do you have a specific vertex fraction? vertex = -b/2a wuadratic = ax^ + bx + c
You use standard form in algebra because you have to know the number before you answer the problem
You can convert standard form to factored form by using a factoring tree to convert to the long-form factored format. You can also work backwards to convert from factored to standard form.
Well, if we're talking algebra, then standard form is ax+by=c
That already is in standard form.
There are two forms in which a quadratic equation can be written: general form, which is ax2 + bx + c, and standard form, which is a(x - q)2 + p. In standard form, the vertex is (q, p). So to find the vertex, simply convert general form into standard form.The formula often used to convert between these two forms is:ax2 + bx + c = a(x + b/2a)2 + c - b2/4aSubstitute the variables:-2x2 + 12x - 13 = -2(x + 12/-4)2 -13 + 122/-8-2x2 + 12x - 13 = -2(x - 3)2 + 5Since the co-ordinates of the vertex are equal to (q, p), the vertex of the parabola defined by the equation y = -2x2 + 12x - 13 is located at point (3, 5)
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
Assuming the vertex is 0,0 and the directrix is y=4 x^2=0