Cubic inches = pi*r^2*L wherer = radius of rod = 1/2*diameter and L = length, both measured in inches.
to prevent back and forward i-beam movement
If the rod has a radius of R and a length of L, then total area = 2*pi*R*(R+L) square units.
This depends on what type of steel. The density of carbon steel (one of the most common types of steel) is 7.85g/cm3Density = m/vradius of rod = 3.25mm (radius is 1/2 of diameter)3.25mm = .325 cm1 meter = 100cmvolume of cylinder = (pi)(radius)^2(h) = 33.18Density * Volume = mass7.85 * 33.18 = 260.46260.46 grams
Assuming it is a rod, the difficulty lies in that it can't measure the diameter of the beaker. Unless you were to attempt to find out the Radius/Diameter, then work out the circumference from that.
i'am not sure if the radius rod and radius bar are the same on a twin i- beam truck
Coil sprung, solid axle, with radius arms and a panhard rod.
6.2
Im not sure what you mean by a pure rod, but if you are talking about a solid rod, which is simply a cylinder, you can calculate its area as follows: πDL+(πR²)2 Which is pi times the diameter times the length plus pi times the radius squared multiplied by 2.
"Solid Steel" would not be a pipe- it would be a rod. Weight of pipe will vary depending on the thickness of the wall of the pipe.
By stronger, we need to define the loading conditions of the rod or pipe. The strength of a rod or pipe is typically evaluated with axial, transverse (bending), and torsion loads. With the same diameter and the same material, a solid rod is stronger than a hollow pipe. However, with the same weight and material, the hollow pipe is stronger than a solid rod. Because a hollow pipe is lighter than a solid rod at the same diameter, the hollow pipe would have a larger diameter in order to match weights with the solid rod and a larger diameter rod or pipe is stronger than a smaller diameter one.
Yes, a solid rod of copper is a better conductor than a hollow rod of copper because the solid rod has more metallic structure and more pathways for electrons to move through. In contrast, the hollow rod has less material and fewer pathways for electron flow, resulting in higher resistance to electrical conduction.
an ebonite rod is a solid in which you find little black phosterus in
Area of rod = length*diameter*pi
First, you need to know the mass of brass: Brass, Specific Gravity 8.56 lb per Cubic Foot (from wikianswers) second: you need to know the length and radius of the rod. formula: divide the radius of the rod by two square the answer you get (multiply it by itself) multiply by pi You have now calculate the area of the rod's end. multiply the answer by the length of the rod and you get the volume of the rod finally, multiply the answer by the specific gravity for brass. The answer is the weight of the brass rod NOTE: make sure you use the same units for length and mass throughout the formula. In the above example you will have to know the radius and length in feet to yield the weight in lbs. If you want to know the answer in a different unit (ounces for example) you will have to convert the specific gravity to correct units.
Cubic inches = pi*r^2*L wherer = radius of rod = 1/2*diameter and L = length, both measured in inches.
to prevent back and forward i-beam movement