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Please can you clarify the following points

(i) should there be a + or - sign between x and 1?

(ii) do you mean everything in the bracket to the power of -3?

I would rewrite this as 20(x+1)^-3 or 20(x-1)^-3 where the ^ means 'to the power of'

If it is one of these last two, then differentiating you would get

-3*20*(x+1)^-4 or -3*20*(x-1)^-4 (8 means multiplied by )

or simplifying

-60(x+1)^-4 or -60(x-1)^-4

Q: How do you differentiate 20((x 1)-3)?

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20x=130 x=130/20 x=6.5 or 13/2

3x - 7 = 5x + 13-2x = 20x = -10

3x - 7 = 5x + 133x - 5x = 13 + 7-2x = 20x = -10x=-3

280

(12/13)x = 20x = 20 / (12/13) = (20 x 13) / 12 = 21 and 2/3

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20x=130 x=130/20 x=6.5 or 13/2

3x - 7 = 5x + 13-2x = 20x = -10

7x=20+20x collect terms containg x on one side and then factorize -13x=20 0r, x=-20/13

3x - 7 = 5x + 133x - 5x = 13 + 7-2x = 20x = -10x=-3

20x

It is the same as: 9+20x+20 = 20x+29

280

If the equation is -20x-5y=40 then the answer is -5y=20x+40 which equals y=-4x-8 If the equation is -20x+5y=40 then the answer is 5y=20x+40 which equals y=4x+8

If: 20x = 3.65 Then: x = 0.1825

(12/13)x = 20x = 20 / (12/13) = (20 x 13) / 12 = 21 and 2/3

-5x2 + 20x - 13 describes a parabola, and you can find it's vertex in various ways. To find it using calculus, you can simply take it's derivative and solve for 0: f(x) = -5x2 + 20x - 13 f'(x) = -10x + 20 Let f'(x) = 0, then: 0 = -10x + 20 x = 2 Then simply plug the x value into the original equation: f(x) = -5 * 22 + 20 * 2 - 13 = -20 + 40 - 13 = 7 So the vertex of this parabola is at the point (2, 7). To solve it using strictly algebra, you can do it by expressing it as a value of y, and then rearranging accordingly: y = -5x2 + 20x - 13 y = -5(x2 - 4x) - 13 y = -5(x2 - 4x + 4 - 4) - 13 y = -5(x2 - 4x + 4) + 20 - 13 y = -5(x - 2)2 + 7 From which we can see that the vertex happens at the point (2, 7)

The GCF is 20x.