-5x2 + 20x - 13 describes a parabola, and you can find it's vertex in various ways. To find it using calculus, you can simply take it's derivative and solve for 0:
f(x) = -5x2 + 20x - 13
f'(x) = -10x + 20
Let f'(x) = 0, then:
0 = -10x + 20
x = 2
Then simply plug the x value into the original equation:
f(x) = -5 * 22 + 20 * 2 - 13
= -20 + 40 - 13
= 7
So the vertex of this parabola is at the point (2, 7).
To solve it using strictly algebra, you can do it by expressing it as a value of y, and then rearranging accordingly:
y = -5x2 + 20x - 13
y = -5(x2 - 4x) - 13
y = -5(x2 - 4x + 4 - 4) - 13
y = -5(x2 - 4x + 4) + 20 - 13
y = -5(x - 2)2 + 7
From which we can see that the vertex happens at the point (2, 7)
5x2 + 9x + 4 = (x + 1)(5x + 4).
260 !! :)
-1
Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.
3
5x2 + 9x + 4 = (x + 1)(5x + 4).
260 !! :)
-1
5x2 + 3x - 1 does not have rational factors.
Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.
The answer is 37.
3
= 5x2+70-16+9x-2 = 5x2+9x+52 = 5x2+9x1+52 This implies coefficient of degree 1 is 9. Ans.
5x2-46x+9 = (5x-1)(x-9)
5x2 + 20x = 5x (x + 4)
10x3 + 3x2
The vertex is (-9, -62).