If you have a diagram, divide it equally in six peices, then take three groups of two and erase the line in between the twos.
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first divide the hexagon into three parts a rectangle and two triangles then try to findthe areas of all and then take individual heights and add them to get the height of the hexagon
dont ask me, ask mathematicions
Assuming you have a regular hexagon, drawing a line between every other vertex and the center will give you three congruent quadrilaterals (that also happen to be parallelograms... in fact, they are rhombuses).
Just one diagonal will divide a hexagon into two halves
It is possible to divide a hexagon into 4 or more - up to infinitely many - triangles.