If you have a diagram, divide it equally in six peices, then take three groups of two and erase the line in between the twos.
first divide the hexagon into three parts a rectangle and two triangles then try to findthe areas of all and then take individual heights and add them to get the height of the hexagon
dont ask me, ask mathematicions
Assuming you have a regular hexagon, drawing a line between every other vertex and the center will give you three congruent quadrilaterals (that also happen to be parallelograms... in fact, they are rhombuses).
Just one diagonal will divide a hexagon into two halves
Shapes that can be divided into three equal parts are typically equilateral triangles, hexagons, and circles. Equilateral triangles have three equal sides and angles, making it easy to divide into three equal parts. Hexagons have six sides, which can be divided into three equal parts by drawing lines from one vertex to the opposite side. Circles can also be divided into three equal parts by drawing two diameters that intersect at the center, creating three equal sectors.
Oh, what a lovely question! To divide a hexagon into three equal parts, simply draw lines from each corner to the opposite side, creating three smaller triangles within the hexagon. Each of these triangles will be equal in size, creating three equal parts of the hexagon. Just remember to take your time, have fun, and trust in your own unique creativity.
first divide the hexagon into three parts a rectangle and two triangles then try to findthe areas of all and then take individual heights and add them to get the height of the hexagon
Select any point inside the hexagon and draw a line segment to any point on the boundary of the hexagon. Draw 7 more such segments. These will divide the hexagon into 8 parts. The parts will not be equal but that was not a requirement of the question.
Oh, what a lovely question! To divide a hexagon into 6 equal parts, simply draw lines from each corner of the hexagon to the center. This will create 6 equal triangles within the hexagon, each with the same size and shape. Remember, there are many ways to divide and create beauty in this world, just like there are many ways to divide a hexagon!
dont ask me, ask mathematicions
Assuming you have a regular hexagon, drawing a line between every other vertex and the center will give you three congruent quadrilaterals (that also happen to be parallelograms... in fact, they are rhombuses).
Divide it into 72 pieces, group them into groups of 8. DoNe
Assuming the hexagon is equilateral (all six sides are the same length) 1) Draw a straight line from each angle in the hexagon (where the sides meet each other) to the angle on the opposite side of the hexagon. You have divided the hexagon into 6 parts now. 2) Find the center point of each line forming the sides of the hexagon. Draw a line from each center point to the opposite side's center point so that all lines drawn are at right angles to the sides. You will have 12 equal parts
In general it cannot be done. In the rare case that the hexagon is regular, select three alternate vertices and draw lines to the centre (centroid) of the hexagon. These will form three congruent rhombi.
Draw a line from midpoint of every other side to the center.
A circle can.
Just one diagonal will divide a hexagon into two halves