first divide the hexagon into three parts a rectangle and two triangles then try to findthe areas of all and then take individual heights and add them to get the height of the hexagon
dont ask me, ask mathematicions
Assuming you have a regular hexagon, drawing a line between every other vertex and the center will give you three congruent quadrilaterals (that also happen to be parallelograms... in fact, they are rhombuses).
Just one diagonal will divide a hexagon into two halves
It is possible to divide a hexagon into 4 or more - up to infinitely many - triangles.
To divide a hexagon into three equal parts, you can draw lines from each vertex to the opposite side's midpoint, creating six smaller triangles within the hexagon. Then, draw a line connecting the midpoints of two opposite sides. This line will divide the hexagon into three equal parts, each containing two of the smaller triangles. This method ensures that each part has an equal area and maintains the symmetry of the hexagon.
first divide the hexagon into three parts a rectangle and two triangles then try to findthe areas of all and then take individual heights and add them to get the height of the hexagon
Select any point inside the hexagon and draw a line segment to any point on the boundary of the hexagon. Draw 7 more such segments. These will divide the hexagon into 8 parts. The parts will not be equal but that was not a requirement of the question.
Partitioning a general hexagon into 6 equal parts is normally extremely difficult..
dont ask me, ask mathematicions
Assuming you have a regular hexagon, drawing a line between every other vertex and the center will give you three congruent quadrilaterals (that also happen to be parallelograms... in fact, they are rhombuses).
Divide it into 72 pieces, group them into groups of 8. DoNe
Assuming the hexagon is equilateral (all six sides are the same length) 1) Draw a straight line from each angle in the hexagon (where the sides meet each other) to the angle on the opposite side of the hexagon. You have divided the hexagon into 6 parts now. 2) Find the center point of each line forming the sides of the hexagon. Draw a line from each center point to the opposite side's center point so that all lines drawn are at right angles to the sides. You will have 12 equal parts
In general it cannot be done. In the rare case that the hexagon is regular, select three alternate vertices and draw lines to the centre (centroid) of the hexagon. These will form three congruent rhombi.
Draw a line from midpoint of every other side to the center.
A circle can.
Just one diagonal will divide a hexagon into two halves