You take a guess as to an approximate square root, for example 2, which is the square root of 2. You divide 5 by 2, to get 2.5. The real square root will be between 2 and 2.5, so you take the average of these two (2.25). You divide 5 by 2.25 to get the next approximation. Repeat a few times, until you have the desired accuracy.
it would be 16,00 because any time you want a square root of a number you always no matter what you will divide by 2
You can combine square roots when you multiply or divide. For example: root(2) x root(3) = root(6). You cannot do the same for addition and subtraction. For example, root(2) + root(3) can't be simplified.
You can use logrithms.Take your log table.Look for the log value of 2.Now divide that value by 2(you should devide by 2 if you want square root,devide by 3 if you want cubic root).Now take the antilog value.It is equal to square root.
Divide the square root by itself
Using the order of operations, the answer is 2 + sqrt(2).
Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5
2
2
The solution is to divide 343 by the square root of 2... That will give you the missing number.
Two to the power 8 (28) is 256 The square root of 256 is 16. When you take the square root of a number raised to a power y, divide that power by 2 (y/2) and that gives the square root. So the square root of 28 = 28/2 = 24 = 16
You take a guess as to an approximate square root, for example 2, which is the square root of 2. You divide 5 by 2, to get 2.5. The real square root will be between 2 and 2.5, so you take the average of these two (2.25). You divide 5 by 2.25 to get the next approximation. Repeat a few times, until you have the desired accuracy.
50
it would be 16,00 because any time you want a square root of a number you always no matter what you will divide by 2
You can combine square roots when you multiply or divide. For example: root(2) x root(3) = root(6). You cannot do the same for addition and subtraction. For example, root(2) + root(3) can't be simplified.
You can use logrithms.Take your log table.Look for the log value of 2.Now divide that value by 2(you should devide by 2 if you want square root,devide by 3 if you want cubic root).Now take the antilog value.It is equal to square root.
1: Calculate the square root, then calculate its square root; OR 2: Take the logarithm of the number, divide it by 4 then take the antilog.