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Suppose you have n objects and within those, there arem1 objects of kind 1
m2 objects of kind 2
and so on.
Then the number of permutations of the n objects is n!/[m1!* m2!...]
For example, permutations of the word "banana"
n = 6
there are 3 "a"s so m1 = 3
there are 2 "n"s so m2 = 2
therefore, the number of permutations = 6!/(3!*2!) = 720/(3*2) = 120.
What else can I help you with?
How many permutations of the letters in the word noon are there?
The word "noon" consists of 4 letters, where 'n' appears twice and 'o' appears twice. To find the number of distinct permutations, we use the formula for permutations of multiset: ( \frac{n!}{n_1! \cdot n_2!} ), where ( n ) is the total number of letters and ( n_1, n_2 ) are the frequencies of the repeating letters. Thus, the number of permutations is ( \frac{4!}{2! \cdot 2!} = \frac{24}{4} = 6 ). Therefore, there are 6 distinct permutations of the letters in the word "noon."
How many distinguishable and indistinguishable permutations are there in the word algrebra?
The word "algrebra" has 8 letters, with the letter 'a' appearing twice and 'r' appearing twice. To find the number of distinguishable permutations, we use the formula for permutations of multiset: ( \frac{n!}{n_1! \times n_2!} ), where ( n ) is the total number of letters and ( n_1, n_2 ) are the frequencies of the repeating letters. Thus, the number of distinguishable permutations is ( \frac{8!}{2! \times 2!} = 10080 ). Since all letters are counted in this formula, there are no indistinguishable permutations in this context.
How many 3 digit codes are possible with out repeating a number using 0-9 only?
10 x 9 x 8 = 720 different "permutations"
How many permutations does the string ABC have?
3x2x1=6 permutations.
What is the permutations and combinations for the word great?
There are 120 permutations and only 1 combination.
How many permutations of the letters in the word noon are there?
The word "noon" consists of 4 letters, where 'n' appears twice and 'o' appears twice. To find the number of distinct permutations, we use the formula for permutations of multiset: ( \frac{n!}{n_1! \cdot n_2!} ), where ( n ) is the total number of letters and ( n_1, n_2 ) are the frequencies of the repeating letters. Thus, the number of permutations is ( \frac{4!}{2! \cdot 2!} = \frac{24}{4} = 6 ). Therefore, there are 6 distinct permutations of the letters in the word "noon."
How many distinguishable and indistinguishable permutations are there in the word algrebra?
The word "algrebra" has 8 letters, with the letter 'a' appearing twice and 'r' appearing twice. To find the number of distinguishable permutations, we use the formula for permutations of multiset: ( \frac{n!}{n_1! \times n_2!} ), where ( n ) is the total number of letters and ( n_1, n_2 ) are the frequencies of the repeating letters. Thus, the number of distinguishable permutations is ( \frac{8!}{2! \times 2!} = 10080 ). Since all letters are counted in this formula, there are no indistinguishable permutations in this context.
How many 3 digit codes are possible with out repeating a number using 0-9 only?
10 x 9 x 8 = 720 different "permutations"
How many permutations does the string ABC have?
3x2x1=6 permutations.
How many permutations can you get out of an eight word phrase?
There are 8! = 40320 permutations.
What is the permutations and combinations for the word great?
There are 120 permutations and only 1 combination.
How many permutations in obfuscation?
If you mean permutations of the letters in the word "obfuscation", the answer is 1,814,400.
How many permutations are possible of the letters in the word Fresno?
There are 6! = 720 permutations.
How many permutations are possible of the word information?
39916800 permutations are possible for the word INFORMATION.
How many permutations are in the word arithmetic?
10! permutations of the word "Arithmetic" may be made.
How many 3 letter permutations of the word October?
There are 195 3-letter permutations.
What is the permutations of freezer?
A freezer is a freezer: it has a fixed shape and a fixed purpose so there are really no permutations.
