Suppose you have n objects and within those, there arem1 objects of kind 1
m2 objects of kind 2
and so on.
Then the number of permutations of the n objects is n!/[m1!* m2!...]
For example, permutations of the word "banana"
n = 6
there are 3 "a"s so m1 = 3
there are 2 "n"s so m2 = 2
therefore, the number of permutations = 6!/(3!*2!) = 720/(3*2) = 120.
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10 x 9 x 8 = 720 different "permutations"
3x2x1=6 permutations.
There are 120 permutations and only 1 combination.
There are 195 3-letter permutations.
10! permutations of the word "Arithmetic" may be made.