startn=0n=n/1
n-11
after u draw the chart , u decide to work on the early finish or the late finish , and this called t1 .. and nw u have 2 get the time that the activity end on and that's called t2 , t2= t1 + ( (N-1)/R ) N = number of repetitive units R = Rate = number of crew / duration now draw y-axis and x-axis , then draw a parallel line to x-axis at point N on y-axis ,, where the y-axis represent the number of units start from 1 and the (lower) x axis represent the t1 and the ( upper ) x-axis represent the t2
start n=1,0 print n n>=99,100 yes end no n=n+2 back to print step
An n-gon has n(n-3)/2 total diagonals. You can draw n-3 diagonals from each vertex ( n>3) ( A triangle doesn't really have a diagonal) An alternative way of seeing this: from any vertex, you can draw a diagonal to any other vertex except itself and the immediate neighbour on either side (the latter would be sides of the n-gon). This gives n-3 diagonals.
startn=0n=n/1
N
20017
draw a circle and the n draw a tail
1. Read in 'n'2. Output n*(n+1)/2> Check the no. in odd or even?Both possible, has no significance.
n-11
You draw the canels n oceans then u
Netball
you get a pencil n paper then u put the pencil oon the paper n u draw the wings... the end (^3^) YAY stupidity!!!
The activity of a radioactive sample is calculated using the formula: Activity = λ*N, where λ is the decay constant of the isotope and N is the number of radioactive nuclei present in the sample. The unit of activity is becquerel (Bq).
class table{public static void main(String args[])int n=2;System.out.println("Table of " + n + " is :");int result;for (int a = 1; a
T = N + 25 and S = 2N - 3So N + 25 < 2N - 3N < 2N - 28-N < -28N > 28