To solve the system of equations (4x + 8y = 20) and (-4x + 2y = -3), you can use the elimination method. First, add the two equations together to eliminate (x):
[ (4x - 4x) + (8y + 2y) = 20 - 3 ]
This simplifies to (10y = 17), giving (y = \frac{17}{10}). Substitute (y) back into either original equation to find (x). For example, using (4x + 8(\frac{17}{10}) = 20), you can solve for (x).
4x+2y = 20 2y = -4x+20 y = -2x+10
x+2y = 7 2y = -x+7 y = -0.5x+3.5
4x + 2y = 20 2y = -4x + 20 y = -2x + 10.......but you may also write it as y = 10 - 2x.
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
63 + 20 - 60 = 23
4x+2y = 20 2y = -4x+20 y = -2x+10
4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
x+2y = 7 2y = -x+7 y = -0.5x+3.5
4x + 2y = 20 2y = -4x + 20 y = -2x + 10.......but you may also write it as y = 10 - 2x.
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
63 + 20 - 60 = 23
x = -4 and y = 4
3x+2y-5=0 3x+2y=5 Im lost im only 12 work out the rest hope i helped
This means that 2y - 3 = 2y + 4 which is not possible.
y=16 x= -4
y = -2x+10
The solution is:- x = 0 and y = 5