Well, you know that in order to classify a shape as a rectangle all of the sides have to be congruent or 90 degrees. If you draw the diagonal of that rectangle, you come up with two right triangles. So you can use the Pythagorean theorem (a squared+b squared=c squared) to find out the diagonal. Ex: If the length=4, and width=3, then diagonal=5, because 4 squared+3 squared=5 squared.
26cm
A rectangle with the area of 2cm squared could be: 2x1 4x0.5 8x0.25 10x0.2 16x0.125 etc there are an infinite amount of possibilities
80 meters
35
The width will be 30cm
Well, you know that in order to classify a shape as a rectangle all of the sides have to be congruent or 90 degrees. If you draw the diagonal of that rectangle, you come up with two right triangles. So you can use the Pythagorean theorem (a squared+b squared=c squared) to find out the diagonal. Ex: If the length=4, and width=3, then diagonal=5, because 4 squared+3 squared=5 squared.
26cm
A rectangle with the area of 2cm squared could be: 2x1 4x0.5 8x0.25 10x0.2 16x0.125 etc there are an infinite amount of possibilities
80 meters
35
Draw one whole in ONE rectangle, and draw the thirds in a different rectangle..!
it is possible to draw a square that is a rectangle?
The area of rectangle is : 18.0
Draw a rectangle and draw three lines in it.... Firstly, draw 3 lines and divide one line into two...then it will easy to draw a rectangle...
To find the area of a regular hexagon with side length of 40cm, consider that since it is regular, then it consists of 6 equilateral triangles of side 40cm. Half of each of those triangles is a right triangle. By the pythagorean theorem, we know that if the hypotenuse is 40cm, and one side is 20cm, then the other side is the square root of (40cm squared - 20cm squared) or about 34.64cm. That makes the area of each of those 12 right triangle to be about 692.8cm, so the total area of the hexagon is about 8313.8cm.
One possibility is 15 x 5 (therefore perimeter is 15 x 15 x 5 x 5 = 40cm).