Wiki User
∙ 11y agoWant this question answered?
Be notified when an answer is posted
Select any number, B, less than or equal to 3 units. Let L = 6 - B units. Then, a rectangle with length L and breadth B will have a perimeter of 12 units.
0.000...1cm length on two sides. 19.999...9cm length on the other two.
Yes 3x5
10 ------------------------------- | | 0.5 -------------------------------
5x2 + 3x2 = 16
The rectangle would have a width of 2 and a length of 4.
The rectangle is in fact a square with 4 equal sides of 5 units in length.
The formula for the perimeter of a rectangle is: p = 2(l + w) In other words, just add all four sides. You can't calculate the perimeter of the rectangle if you know only the length.
It's impossible. The largest area for a rectangle with perimeter of 6 is 2.25, a perfect square with a length of 1.5 for each side. Any other combination yields a smaller area.
Select any number, B, less than or equal to 3 units. Let L = 6 - B units. Then, a rectangle with length L and breadth B will have a perimeter of 12 units.
0.000...1cm length on two sides. 19.999...9cm length on the other two.
Since the perimeter is 18, the sum of the length and breadth is 18/2 units = 9 units. Draw a straight line on the grid of less than 9 units. At right angles to that line, draw another line so that the two lines have a combined length of 9 units. These two lines are the two adjacent lines of the rectangle. Use the grid to draw line parallel to these so that you have a rectangle.
Yes 3x5
The rectangle has dimensions of [ 12 x 3 ].
10 ------------------------------- | | 0.5 -------------------------------
Yes, draw a 2 x 7 rectangle.
No. If you draw a rectangle there are four sides, the length of two of those sides are equal to the length, and the other two are equal to the width. Therefore: the perimeter, which is equal to all the sides added up, is equal to two times the length plus two times the width: or 2L+2W= Perimeter. If you know L and you know the perimeter you can solve it algebraically. the width equals the perimeter minus two times the length, all that divided by two, or W= (P-2L)/2 (when you do the algebra). you might be thinking about the area in which case if you knew the area and the length and you want to find the width you would divide the area by the length.