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It's impossible. The largest area for a rectangle with perimeter of 6 is 2.25, a perfect square with a length of 1.5 for each side. Any other combination yields a smaller area.

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Q: Who do you draw a rectangle with the Area 4 perimeter 6?
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The rectangle would have a width of 2 and a length of 4.


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If sides of rectangle A to rectangle B has ratio 4 to 5. What would the perimeter of rectangle A if the rectangle B has a perimeter of 100 What about area of Rectangle A if the area of rectangle B is?

The perimeter of rectangle A would then be 80 because 80 to 100 is 4 to 5 simplified and the area of triangle A would depend on the sides and area of rectangle B which have not been given.


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A rectangle has a perimeter of 10 ft Write the area A of the rectangle as a function of the length of one side x of the rectangle?

This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.