Eight 4 inch cubes are needed to build and 8 inch cube.
u draw a cube and count the vertices... a cube has 8 vertices
8*8*8 = 512 cubic inches.
Entire surface area: 6*8*8 = 384 square inches
The volume of the little cube is 23 = 8 cubic inches so the density of the material is 8/20 = 0.4 grams per cubic inch.The volume of the large cube is 83 = 512 cubic inches, so the mass (not the weight) is 512*0.4 = 128 grams.
Eight 4 inch cubes are needed to build and 8 inch cube.
u draw a cube and count the vertices... a cube has 8 vertices
volume 4 in cube = 4 x 4 x 4 = 64 cuins volume 8 in cube = 8 x 8 x 8 = 512 cuins Yes is the short answer.
8*8*8 = 512 cubic inches.
To find the volume of a cube V = s^3. Therefore a cube with a side of 8 inches is calculated like 8 x 8 x 8 which equals 512.
The number of concrete blocks in a cube depends on the size and style of the blocks. For 6-inch by 4-inch by 16-inch blocks, there are generally either 100 or 120 per cube. For blocks that are 8 inches by 8 inches by 16 inches, there are usually either 75 or 90 per cube.
a 10 inch cube is bigger than a 5 inch cube
Entire surface area: 6*8*8 = 384 square inches
8
To find the total surface area of the 3-cube tower, we need to calculate the surface area of each cube individually and then add them together. The surface area of a cube is given by 6 times the side length squared. For the 3-inch cube: 6 * 3^2 = 54 square inches For the 2-inch cube: 6 * 2^2 = 24 square inches For the 1-inch cube: 6 * 1^2 = 6 square inches Adding these together: 54 + 24 + 6 = 84 square inches Therefore, the total surface area of the 3-cube tower is 84 square inches.
The volume of the little cube is 23 = 8 cubic inches so the density of the material is 8/20 = 0.4 grams per cubic inch.The volume of the large cube is 83 = 512 cubic inches, so the mass (not the weight) is 512*0.4 = 128 grams.
cut it in 8 squires then draw the net and stick it according 2 the net