Kistos
sinx = sin0 = 0
tanx = tan0 = 0
you have 0/0 by you limit conditions
Wiki User
∙ 13y agoIt depends on the exact value of h, but, algebraically, the answer is h/24.
You can use the L'hopital's rule to calculate the limit of e5x -1 divided by sin x as x approaches 0.
124.3784
100 divided by (5*2-3*3) = 100 divided by 1 = 100 So the answer is: 100
0
Expressed algebraically, this is equal to x/4.
It depends on the exact value of h, but, algebraically, the answer is h/24.
It cannot be simplified algebraically and needs to be calculated.
Algebraically, you would write this as '7/x'.
3 and one-seventh
1.6
You can use the L'hopital's rule to calculate the limit of e5x -1 divided by sin x as x approaches 0.
3
For any value divided by zero the answer is "infinite" or "undefined". Think about it. X divided by 1 is X. X divided by 1/2 is 2X. X divided by 1/4 is 4X. As the divisor gets smaller, the result gets larger. As the divisor approaches zero, the result approaches infinity.
Newton's second law states that acceleration is directly proportional to the net force acting on an object and inversely proportional to its mass. This relationship is mathematically represented as F = ma, where F is the force, m is the mass of the object, and a is the acceleration.
124.3784
100 divided by (5*2-3*3) = 100 divided by 1 = 100 So the answer is: 100