sinx = sin0 = 0
tanx = tan0 = 0
you have 0/0 by you limit conditions
It depends on the exact value of h, but, algebraically, the answer is h/24.
You can use the L'hopital's rule to calculate the limit of e5x -1 divided by sin x as x approaches 0.
124.3784
100 divided by (5*2-3*3) = 100 divided by 1 = 100 So the answer is: 100
0
Expressed algebraically, this is equal to x/4.
It depends on the exact value of h, but, algebraically, the answer is h/24.
It cannot be simplified algebraically and needs to be calculated.
The algebraic term is: 7/x
3 and one-seventh
1.6
You can use the L'hopital's rule to calculate the limit of e5x -1 divided by sin x as x approaches 0.
3
For any value divided by zero the answer is "infinite" or "undefined". Think about it. X divided by 1 is X. X divided by 1/2 is 2X. X divided by 1/4 is 4X. As the divisor gets smaller, the result gets larger. As the divisor approaches zero, the result approaches infinity.
124.3784
100 divided by (5*2-3*3) = 100 divided by 1 = 100 So the answer is: 100
9x/2x = 9/2 = 4.5