0
Add your answer:
Earn +20 pts
The sum of three consecutive numbers is 276 What are the smallest of these numbers?
91 are.
What are the three consecutive odd integers with a sum of -279?
The numbers are -95, -93, and -91.
How do you Factor 91 into prime numbers?
Divide by the smallest primes, 2,3,5,7,11,etc.If it divides without a remainder then it is a factor.Take the quotient and continue factoring by primes.91/2 no91/3 no91/5 no91/7=1313 is prime therefore 91=7 x 13
The sum of three integers is 69 If the first integer is doubled the sum is 77 If the second integer is doubled the sum is 91 Find the integers?
The first integer must equal 77 - 69 = 8 , since doubling it increases the sum by this amount. Similarly, the second integer must = 91 - 69 = 22. Then the third integer is 69 - 22 - 8 = 39.
What is the difference between the exact sum of 106 and 91 and an estimate of the sum by rounding to the nearest hundred?
3
How do you write 91 as a product of primes?
It is: 7 times 13 = 91
The sum of three consecutive numbers is 276 What are the smallest of these numbers?
91 are.
The sum of three consecutive odd integers is -273 what are the integers?
Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.
What is the sum of Three consecutive integers is 273?
They are: 90+91+92 = 273
What are the three consecutive odd integers with a sum of -279?
The numbers are -95, -93, and -91.
If sum of three consecutive multiples of 7 is equal to 252 Find the highest number?
91
How many numbers are prime in the nineties?
There are two primes in the nineties: 91 and 97
What is the sum of the divisors of 36?
Sum of divisors = 91.
How do you Factor 91 into prime numbers?
Divide by the smallest primes, 2,3,5,7,11,etc.If it divides without a remainder then it is a factor.Take the quotient and continue factoring by primes.91/2 no91/3 no91/5 no91/7=1313 is prime therefore 91=7 x 13
What is the sum of all prime numbers between 1 and 100 that are simultaneously one greater than a multiple of 5 and one less than a multiple of 6?
123 To be a multiple of 5 a number ends with 0 or 5. No primes can be even, so no multiple of 5 may end with 5. Without knowing which are primes the possible numbers left are: 11, 21, 31, 41, 51, 61, 71, 81, 91. To be a multiple of 6 is must be even and the digit sum must be dividable by 3. Without knowing which are primes the possible numbers left from the above are: 11, 41 and 71. By a staggering coincidence all those are in fact primes, thus making the sum 123. /C
What is the least common multiple of 13 and 28?
If all of the numbers are primes, or if all except one are primes, then the LCM is the product of all the numbers.Therefore 13x28, =364
The sum of three integers is 69 If the first integer is doubled the sum is 77 If the second integer is doubled the sum is 91 Find the integers?
The first integer must equal 77 - 69 = 8 , since doubling it increases the sum by this amount. Similarly, the second integer must = 91 - 69 = 22. Then the third integer is 69 - 22 - 8 = 39.
