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What is the sum of all prime numbers between 1 and 100 that are simultaneously one greater than a multiple of 5 and one less than a multiple of 6?
Wiki User
∙ 14y ago
123
To be a multiple of 5 a number ends with 0 or 5. No primes can be even, so no multiple of 5 may end with 5. Without knowing which are primes the possible numbers left are: 11, 21, 31, 41, 51, 61, 71, 81, 91.
To be a multiple of 6 is must be even and the digit sum must be dividable by 3. Without knowing which are primes the possible numbers left from the above are: 11, 41 and 71. By a staggering coincidence all those are in fact primes, thus making the sum 123.
/C
Wiki User
∙ 14y ago
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