Its height (h) is side (s) times sin 60 orsqrt(3)/2 times side = .866s
h = .866s
s = h/.866 = 2/sqrt(3) s = 1.154 h
perimeter = s + s + s = 3s = 3 x 2/sqrt(3) = 3.46s
It would depend on the shape that you are asking about. Also, only special shapes could express area as a function of the perimeter.Example: a square: area = s2, where s is the length of a side. Perimeter of a square is 4*s.So if P (for perimeter) = 4 * s, then s = P/4,and A (for area) = s2 = (P/4)2 = P2/16But for a rectangle that is not a square, there is no relationship between area and perimeter.
- tan 60
The "m" in front of a triangle typically stands for "measure" and indicates the measure of the triangle's angles or sides. For example, "m∠A" refers to the measure of angle A in the triangle. This notation is commonly used in geometry to express the size or extent of a geometric figure.
To find the breadth (width) of a rectangle when given the ratio of length to width and the perimeter, you can start by using the perimeter formula: ( P = 2(L + W) ), where ( L ) is the length and ( W ) is the width. If the length to width ratio is given as ( L:W = a:b ), you can express ( L ) as ( L = \frac{a}{b}W ). Substitute this expression into the perimeter formula, solve for ( W ), and then use the perimeter value to find the breadth.
30
Let's express the side length of an equilateral triangle, a, in term of the height h.a = (1/3)(h)(sq.root of 3)The perimeter equals to 3a. So we have:3a = 3[(1/3)(h)(sq.root of 3)] = (h)(sq.root of 3)] = 18(sq.root of 3)
perimeter = 3x Area = x^2 * sqrt(3)/4 Explanation of area: You can divide an equilateral triangle into 2 right triangles, each with a common side we will call y. Area = area of first right triangle + area of second right triangle = (x/2)*y/2 + (x/2)*y/2 = xy/2 Now: y^2 + (x/2)^2 = x^2 so y^2 = x^2 - x^2/4 so y= sqrt(3)x/2 Area = [sqrt(3)x/2] x [x/2] Area = x2 sqrt (3)/ 4
It would depend on the shape that you are asking about. Also, only special shapes could express area as a function of the perimeter.Example: a square: area = s2, where s is the length of a side. Perimeter of a square is 4*s.So if P (for perimeter) = 4 * s, then s = P/4,and A (for area) = s2 = (P/4)2 = P2/16But for a rectangle that is not a square, there is no relationship between area and perimeter.
36 square units. You can't express a perimeter in square units; a perimeter is a length expressed in ordinary units. If the perimeter of this square is 24 units then the answer above is correct.
Suppose the length and width of the rectangle are L and W metres respectively.Then the perimeter, P = 20 m implies that2(L + W ) = 20 => L + W = 10 or W = 10 - L.Then Area = L * W = L * (10 - L) sq metres.
It is 1/4 or 0.25
You use linear units to express it, such as meters or millimeters, if that's what you mean.
To express action
To express action
5*4+4=24cm
- tan 60
No. That can be proven in this way, accepting the truth of the Pythagorean Theorem, which says that the square of the length of the hypotenuse, c, of a right triangle with orthogonal sides a and b, will always be equal to the sum of the squares of the lengths of sides a and b. If c is the length of side c, and so on, the Pythagorean Theorem stated above becomes this mathematical statement: c2 = a2 + b2 One way to test a hypothesis is to express the assumed case, apply logic steps to it, and examine the truth of the result. So if we assume for argument that our right triangle is equilateral, and assign length xequally to all three sides--a, b, & c--we could write the equation thus: x2 = x2 + x2 which becomes x2 = 2(x2) Factoring out x2, we get 1 = 2 We've arrived at a mathematical contradiction, disproving our assumption. There cannot be right-angled equilateral triangles.